gmail.com> writes:
> If I remember correctly it was unique1d in numpy 1.3 that had the
> return_inverse options.
>
> Check the functions in arraysetops for numpy 1.3.
> unique1d is in my help file for numpy 1.2 (which was the fastest for
> me to look up)
>
You're right, again.
unique1d is in
On Tue, Mar 16, 2010 at 9:33 AM, Jorge Scandaliaris
wrote:
> gmail.com> writes:
>
>>
>> If I understand correctly, then you want return_inverse (the original
>> array recoded to using integers 0...len(ctab)-1
>>
>
>> Josef
>
> Right, thanks! I didn't see this cause I use numpy 1.3, where this i
gmail.com> writes:
>
> If I understand correctly, then you want return_inverse (the original
> array recoded to using integers 0...len(ctab)-1
>
> Josef
Right, thanks! I didn't see this cause I use numpy 1.3, where this is
not available.
Jorge
On Tue, Mar 16, 2010 at 8:00 AM, Jorge Scandaliaris
wrote:
> Hi,
> I have a 1D array containing indexes to specific measurements. As this array
> is
> a slice of a bigger one, the indexes don't necessarily start at 0 nor they are
> sequential. For example, I can have an array A where
>
> In [34]:
Hi,
I have a 1D array containing indexes to specific measurements. As this array is
a slice of a bigger one, the indexes don't necessarily start at 0 nor they are
sequential. For example, I can have an array A where
In [34]: A.shape
Out[34]: (4764,)
In [35]: ctab = np.unique(A)
In [36]: ctab
Out[3
