> You'd want to update your mask appropriately to get everything you
> want to select, one criteria at a time e.g.:
> mask = a[:,0] == 1
> mask &= a[:,1] == 1960
>
> Alternatively:
> mask = (a[:,0] == 1) & (a[:,1] == 1960)
> but be careful with the parens, & and | are normally high-priority
> bitw
On Mon, Jan 30, 2012 at 11:31 AM, Ted To wrote:
> On 01/30/2012 12:13 PM, Brett Olsen wrote:
>> On Mon, Jan 30, 2012 at 10:57 AM, Ted To wrote:
>>> Sure thing. To keep it simple suppose I have just a two dimensional
>>> array (time,output):
>>> [(1,2),(2,3),(3,4)]
>>> I would like to look at all
> Thanks! That works great if I only want to search over one index but I
> can't quite figure out what to do with more than a single index. So
> suppose I have a labeled, multidimensional array with labels 'month',
> 'year' and 'quantity'. a[['month','year']] gives me an array of indices
> but "
On 01/30/2012 12:13 PM, Brett Olsen wrote:
> On Mon, Jan 30, 2012 at 10:57 AM, Ted To wrote:
>> Sure thing. To keep it simple suppose I have just a two dimensional
>> array (time,output):
>> [(1,2),(2,3),(3,4)]
>> I would like to look at all values of output for which, for example time==2.
>>
>>
On Mon, Jan 30, 2012 at 10:57 AM, Ted To wrote:
> Sure thing. To keep it simple suppose I have just a two dimensional
> array (time,output):
> [(1,2),(2,3),(3,4)]
> I would like to look at all values of output for which, for example time==2.
>
> My actual application has a six dimensional array a
Sure thing. To keep it simple suppose I have just a two dimensional
array (time,output):
[(1,2),(2,3),(3,4)]
I would like to look at all values of output for which, for example time==2.
My actual application has a six dimensional array and I'd like to look
at the contents using one or more of the
Ted, can you clarify what you're asking for? Maybe give a trivial example of an
array and the desired output?
I'm pretty sure this is a slicing question though:
> If I have a three dimensional array a=(x,y,z), can I look at the values of z
> given particular values for x and y?
Given that elemen
he is not asking for slicing. he is asking for how to index array by
element value but not element index.
2012/1/30 Zachary Pincus
> a[x,y,:]
>
> Read the slicing part of the tutorial:
> http://www.scipy.org/Tentative_NumPy_Tutorial
> (section 1.6)
>
> And the documentation:
> http://docs.scipy.
a[x,y,:]
Read the slicing part of the tutorial:
http://www.scipy.org/Tentative_NumPy_Tutorial
(section 1.6)
And the documentation:
http://docs.scipy.org/doc/numpy/reference/arrays.indexing.html
On Jan 30, 2012, at 10:25 AM, Ted To wrote:
> Hi,
>
> Is there some straightforward way to access
On Mon, Jan 30, 2012 at 3:25 PM, Ted To wrote:
> Is there some straightforward way to access an array by values across a
> subset of its dimensions? For example, if I have a three dimensional
> array a=(x,y,z), can I look at the values of z given particular values
> for x and y?
a[x, y, :] shoul
I am afraid you have to write index inquire function by yourself. I did
like this.
chao
2012/1/30 Ted To
> Hi,
>
> Is there some straightforward way to access an array by values across a
> subset of its dimensions? For example, if I have a three dimensional
> array a=(x,y,z), can I look at the
Hi,
Is there some straightforward way to access an array by values across a
subset of its dimensions? For example, if I have a three dimensional
array a=(x,y,z), can I look at the values of z given particular values
for x and y?
Thanks,
Ted
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