Quick comment since I was working on timing trivial operations,
If I run the triple loop with R with only zeros thus avoiding the
integration, the loop takes in my computer about 1 second with the
float() function and about 1.5 without it if R is dtype='float64' and
3.3 seconds if dtype='float3
On Sun, Dec 30, 2012 at 3:41 AM, Happyman wrote:
> nums=32
> rows=120
> cols=150
>
> for k in range(0,nums):
> for i in range(0,rows):
> for j in range(0,cols):
> if float ( R[ k ] [ i ] [ j ] ) ==
> 0.0:
why the float() -- what
Le dimanche 30 décembre 2012 à 16:47 +0400, Happyman a écrit :
> Actually
> These two functions namely F1 and F2 are really exponential and Bessel
> functions respectively. But I can not change its analytic form..
>
> I mean is there way to get more quickly the result?
> Let's say above mentione
Actually
These two functions namely F1 and F2 are really exponential and Bessel
functions respectively. But I can not change its analytic form..
I mean is there way to get more quickly the result?
Let's say above mentioned two functions, both of them, one function but the
dimension I showed sho
Hello,
> else:
> val11[i][j], val22[i][j] = integrate.quad(lambda x: F1(x)*F2(x), 0, pi)
> But, this calculation takes so long time, let's say about 1 hour
> (theoretically)... Is there any better way to easily and fast calculate
> the process such as [ F( i ) for i in xlist ] or something li
Hello
I have 3 dimensional array which I want to calculate in a huge process.
Everything is working well if I use ordinary way which is unsuitable in Python
like the following:
nums=32
rows=120
cols=150
for k in range(0,nums):
for i in range(0,rows):
for j in
