Hello,
my problem is that i want to remove some small numbers of an 2d array,
for example if i want to sort out all numbers smaller then 1 of an array i
get
x=[[0,1,2],[3,4,5][6,7,8]]
c=x>=1
In [213]: c
Out[213]:
array([[False, True, True],
[ True, True, True],
[ True, Tru
Hi,
is there any possibility to define a numpy matrix, via a smaller given
matrix, i.e. in matlab
i can do this like
a=[1 2 ; 3 4 ]
A=[a a ; a a ]
so that i finally get
A=[ [1,2,1,2]
[3,4,3,4]
[1,2,1,2]
[3,4,3,4]]
i tried different things on numpy which didn't work
ooh , my bad your right
didnt see that thank you
Olivier Delalleau-2 wrote:
>
> You are overriding your f1 function with a float (with
> "f1=f1(self.ptdata[i])"), so trying to call f1(xul) later will raise this
> exception.
>
> -=- Olivier
>
> 2011/6/10
Hello,
i have the following problem, the following code doesnt work
def f1(x): return self.lgdata[2*i][0]*float(x)+self.lgdata[2*i][1]
def f2(x): return self.lgdata[2*i+1][0]*float(x)+self.lgdata[2*i+1][1]
f1=f1(self.ptdata[i])
f2=f2(self.ptdata[i])
t=abs(f1-f2)
deltat.append(t)
temptot.append(f1
Hello,
i have the following problem, the following code doesnt work
def f1(x): return self.lgdata[2*i][0]*float(x)+self.lgdata[2*i][1]
def f2(x): return self.lgdata[2*i+1][0]*float(x)+self.lgdata[2*i+1][1]
f1=f1(self.ptdata[i])
2=f2(self.ptdata[i])
t=abs(f1-f2)
deltat.append(t)
temptot.append(f1)
Bruce Southey wrote:
>
> On 06/03/2011 09:33 AM, jonasr wrote:
>> thank you very much, works much nicer and faster in comparison to the
>> script
>> i wrote and used before ,
>> im not that much used to lambda forms but it seems quit usefull in
>> s
thank you very much, works quit nice and faster in comparison to the script i
wrote and used before ,
im not that much used to lambda forms but it seems quit usefull in
situations like this
Olivier Delalleau-2 wrote:
>
> Here's an ugly one-liner:
>
> numpy.genfromtxt('data.txt', converters=d
