Sorry,
that i use this way to send an answer to Tony Yu , Nadav Horesh , Chris Barker.
When iam direct answering on Your e-mail i get an error 5.
I think i did a mistake.
Your ideas are very helpfull and the code is very fast.
Thank You
elodw
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Counting the Colors of RGB-Image,
nameit im0 with im0.shape = 2500,3500,3
with this code:
tab0 = zeros( (256,256,256) , dtype=int)
tt = im0.view()
tt.shape = -1,3
for r,g,b in tt:
tab0[r,g,b] += 1
Question:
Is there a faster way in numpy to get this result?
MfG elodw
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