Thanks Robert
On Mon, Jun 21, 2010 at 11:47 AM, Robert Kern wrote:
> On Mon, Jun 21, 2010 at 13:40, Vishal Rana wrote:
> > I have tried:
> > x1=np.array([1,2,3,4])
> > x2=np.array(['a','dd','xyz','12'])
> > x3=np.array([1.1
es
So my record is lost and converted to ndarray, any idea?
Thanks
Vishal Rana
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It helped, Thanks
On Wed, Jun 16, 2010 at 10:39 AM, Robert Kern wrote:
> On Wed, Jun 16, 2010 at 12:30, Vishal Rana wrote:
> > Robert,
> > Do I have to repeat it for each element in the list or is there a way I
> can
> > iterate the list and do it?
>
> new_lis
Robert,
Do I have to repeat it for each element in the list or is there a way I can
iterate the list and do it?
Thanks
Vishal Rana
On Wed, Jun 16, 2010 at 10:23 AM, Robert Kern wrote:
> On Wed, Jun 16, 2010 at 12:15, Vishal Rana wrote:
> > Hi,
> > I have a list of np arra
Hi,
I have a list of np arrays from which I create a np record array, but they
all of of different length!
How can I trim them all in place (for example I want to get last 10 elements
of each)?
Thanks
Vishal Rana
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Thanks
On Tue, Jun 15, 2010 at 8:49 PM, Robert Kern wrote:
> On Tue, Jun 15, 2010 at 01:56, Vishal Rana wrote:
> > Robert,
> > As you said, I was able to get the results, but I now got a question as
> > np.load('np.npz') returns me a object so
> does
>
Robert,
As you said, I was able to get the results, but I now got a question as
np.load('np.npz') returns me a object so does
that mean the data is read directly from the from the npz file and not all
the data is loaded to the memory?
Thanks
Vishal Rana
On Mon, Jun 14, 2010 at 5:08
Thanks Robert
On Mon, Jun 14, 2010 at 5:08 PM, Robert Kern wrote:
> On Mon, Jun 14, 2010 at 19:00, Vishal Rana wrote:
> > Hi,
> > I have dictionary of numpy record arrays, what could be fastest way to
> > save/load to/from a disk. I tried numpy.save() but my dic
Hi,
I have dictionary of numpy record arrays, what could be fastest way to
save/load to/from a disk. I tried numpy.save() but my dictionary is lost and
cPickle seems to be slow.
Thanks
Vishal
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Thanks, it worked.
On Mon, Jun 14, 2010 at 7:39 AM, Benjamin Root wrote:
>
>
> On Mon, Jun 14, 2010 at 1:09 AM, David Cournapeau wrote:
>
>> On Mon, Jun 14, 2010 at 3:00 PM, Vishal Rana
>> wrote:
>> > Hi,
>> > I am getting this error while upgr
152, in run
File
"/tmp/easy_install-5_dz2F/numpy-1.4.1/numpy/distutils/command/build_src.py",
line 163, in build_sources
File
"/tmp/easy_install-5_dz2F/numpy-1.4.1/numpy/distutils/command/build_src.py",
line 298, in build_library_sources
File
"/tmp/easy_install-5_d
Thanks Robert, it worked.
On Sun, Jun 13, 2010 at 6:23 PM, Robert Kern wrote:
> On Sun, Jun 13, 2010 at 20:10, Vishal Rana wrote:
> > Robert,
> > There is no error on python side but on flex client which
> > is "Channel.Call.Failed" faultDetail="NetConnecti
thon data types so
I am not sure if numpy dtypes will work with it or not, but it working on
Mac OS X.
Thanks
Vishal Rana
On Sun, Jun 13, 2010 at 6:04 PM, Robert Kern wrote:
> On Sun, Jun 13, 2010 at 19:52, Vishal Rana wrote:
> > I created a record array (from strings and floats) with
ntu 10.04 it fails. Looks like
serialization is failing for type numpy.float64. Is the any work around, I
was trying to set dtype=object is that ok?
Also how can I set same dtype (for eg. object) for all a, b, and c?
Thanks
Vishal Rana
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Thanks Warren!
On Fri, Apr 2, 2010 at 2:46 PM, Warren Weckesser <
warren.weckes...@enthought.com> wrote:
> Vishal Rana wrote:
> > Hi,
> >
> > I know its easy, but I am not just getting it...
> >
> > How do I get last element on axis=1 for:
> >
> &
Hi,
I know its easy, but I am not just getting it...
How do I get last element on axis=1 for:
a = array([[ 0, 1, 2, 3, 4],
[ 5, 6, 7, 8, 9],
[10, 11, 12, 13, 14],
[15, 16, 17, 18, 19],
[20, 21, 22, 23, 24]])
Expected: array([4, 9, 14, 19, 24])
Thanks
Vishal
I get AttributeError: 'NoneType' object has no attribute 'accumulate' for
the call
vecfun.ufunc.accumulate(np.array([0, 1, 2, 3]))
It works fine if I make a dummy call to vecfun before! Any idea for
this behavior?
Thanks
Vishal Rana
On Mon, Mar 29, 2010 at 4:07 AM, Nadav
Thanks Didrik!
On Thu, Apr 1, 2010 at 1:21 AM, Didrik Pinte wrote:
> On Wed, 2010-03-31 at 23:13 -0700, Vishal Rana wrote:
> > Hi,
> >
> >
> > A calculation which goes like this...
> >
> >
> > n = 5
> > a = np.arange(1000)
> > b = np.
if I have like 200K records!
Is there a more efficient way to do this using numpy?
Thanks
Vishal Rana
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That was quick!
Thanks Angus and Zachary
On Tue, Mar 30, 2010 at 11:59 AM, Vishal Rana wrote:
> Hi,
>
> In an array I want to replace all NANs with some number say 100, I found a
> method* **nan_to_num *but it only replaces with zero.
> Any solution for this?
> *
Hi,
In an array I want to replace all NANs with some number say 100, I found a
method* **nan_to_num *but it only replaces with zero.
Any solution for this?
*
*Thanks
Vishal
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as np
>
> vecfun = np.vectorize(func)
>
> vecfun.ufunc.accumulate(array((0,1,2,3,4,5,6,7,8,9))
>
>
> Nadav.
>
>
> -Original Message-----
> From: numpy-discussion-boun...@scipy.org on behalf of Vishal Rana
> Sent: Sun 28-Mar-10 21:19
> To: Discussion of Numeric
Hi,
For a numpy array:
array([0, 1, 2, 3, 4, 5, 6, 7, 8, 9])
I do some calculation with 0, 1... and get a value = 2.5, now use this value
to do the repeat the same calculation with next element for example...
2.5, 2 and get a value = 3.1
3.1, 3 and get a value = 4.2
4.2, 4 and get a value = 5.1
Thanks Friedrich it helped.
On Thu, Feb 18, 2010 at 2:45 AM, Friedrich Romstedt <
friedrichromst...@gmail.com> wrote:
> Hello Vishal,
>
> 2010/2/18 Vishal Rana :
>
> > a = np.array([dt.datetime(2010, 2, 17), dt.datetime(2010, 2, 16),
> > dt.datetime(2010, 2, 15)])
])
Any pointers?
Thanks
Vishal Rana
Joan Crawford<http://www.brainyquote.com/quotes/authors/j/joan_crawford.html>
- "I, Joan Crawford, I believe in the dollar. Everything I earn, I
spend."
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Thanks
On Tue, Feb 9, 2010 at 7:51 AM, Brent Pedersen wrote:
> On Tue, Feb 9, 2010 at 7:42 AM, Vishal Rana wrote:
> > Hi,
> > Is there any utility function to find if values in the array are in
> > ascending or descending order.
> > Example:
> > arr = [1, 2,
Hi,
Is there any utility function to find if values in the array are in
ascending or descending order.
Example:
arr = [1, 2, 4, 6] should return true
arr2 = [1, 0, 2, -2] should return false
Thanks
Vishal
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naries:
>
> In [6]: import numpy as np
>
> In [7]: dt = np.dtype([('name', 'S30'),('age',int),('weight',float)])
>
> In [8]: r = np.array([('Bill',31, 260.0), ('Fred', 15, 145.0)], dtype=dt)
>
> In [9]: r[0]['name
Thanks Robert :)
Vishal Rana
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- "I don't think anyone should write their autobiography until after
they're dead."
On Thu, Feb 4, 2010 at 4:04 PM, Robert Kern wrote:
> On Thu, Feb 4, 2010
How do I convert the numpy record array below:
recs = [('Bill', 31, 260.0), ('Fred', 15, 145.0)]
r = rec.fromrecords(recs, names='name, age, weight', formats='S30, i2, f4')
to a list of dictionary like:
[{'name': 'Bill', 'age': 31, 'weight': 260.0},
'name': 'Fred', 'age': 15, 'weight': 145.0}]
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