ning so that the cumsum starts with zero.
> (Maybe there is a cleaner way to do that.)
>
> This does create a second array (via the repeat) that is the same
> length as the result. If that uses too much memory, you could break
> up the repeat and update of c into segments usi
Pierre GM wrote:
> On Jan 30, 2009, at 1:11 PM, Raik Gruenberg wrote:
>
>> Mhm, I got this far. But how do I get from here to a single index
>> array
>>
>> [ 4, 5, 6, ... 10, 0, 1, 2, 3, 11, 12, 13, 14 ] ?
>
> np.concatenate([np.arange(aa,bb) for (aa,
Jim Vickroy wrote:
> Raik Gruenberg wrote:
>> Hi there,
>>
>> perhaps someone has a bright idea for this one:
>>
>> I want to concatenate ranges of numbers into a single array (for indexing).
>> So I
>> have generated an array "a" with starti
Hi there,
perhaps someone has a bright idea for this one:
I want to concatenate ranges of numbers into a single array (for indexing). So I
have generated an array "a" with starting positions, for example:
a = [4, 0, 11]
I have an array b with stop positions:
b = [11, 4, 15]
and I would like t