time64('1969-12-31 00')
Out[22]: numpy.datetime64('1969-12-31T00:00Z','h')
I saw the other thread about the time zone issues and I think getting rid
of timezones (perhaps unless they are explicitly requested) is the right
thing to do.
Bob
On Tue, Apr 16, 2013 at 4:55 PM, B
At bit OT, but I am new to numpy. The help for np.where says:
Returns
---
out : ndarray or tuple of ndarrays
If both `x` and `y` are specified, the output array contains
elements of `x` where `condition` is True, and elements from
`y` elsewhere.
If on
I am curious if others have noticed an issue with datetime64 at the
beginning of 1970. First:
In [144]: (np.datetime64('1970-01-01') - np.datetime64('1969-12-31'))
Out[144]: numpy.timedelta64(1,'D')
OK this look fine, they are one day apart. But look at this:
In [145]: (np.datetime64('1970-01-01
