Re: [Numpy-discussion] (cube max and reduction)

2012-04-26 Thread Andre Martel
From: eat To: Discussion of Numerical Python Sent: Sunday, April 22, 2012 5:54 AM Subject: Re: [Numpy-discussion] (no subject) Thanks, this was useful. For a large cube, though, I had to loop through the indices of the maxima:     for i in np.arange(0,

[Numpy-discussion] (no subject)

2012-04-20 Thread Andre Martel
What would be the best way to remove the maximum from a cube and "collapse" the remaining elements along the z-axis ? For example, I want to reduce Cube to NewCube: >>> Cube array([[[  13,   2,   3,  42],     [  5, 100,   7,   8],     [  9,   1,  11,  12]],    [[ 25,   4,  15,   1],