On Tue Jul 28 18:18:01 2015 GMT+0200, Matthew Brett wrote:
> On Tue, Jul 28, 2015 at 4:45 PM, Sebastian Berg
> wrote:
> > Yes, I think it is guaranteed C order in the results.
> >
> >
> > On Mon Jul 27 14:05:01 2015 GMT+0200, Matthew Brett wrote:
> >> Hi,
> >>
> >> `np.nonzero` for a 2D array `A`
On Tue, Jul 28, 2015 at 4:45 PM, Sebastian Berg
wrote:
> Yes, I think it is guaranteed C order in the results.
>
>
> On Mon Jul 27 14:05:01 2015 GMT+0200, Matthew Brett wrote:
>> Hi,
>>
>> `np.nonzero` for a 2D array `A` returns:
>>
>> row_inds, col_inds = np.nonzero(A)
>>
>> I notice that `row_in
On Mon Jul 27 22:51:52 2015 GMT+0200, Sturla Molden wrote:
> On 27/07/15 22:10, Anton Akhmerov wrote:
> > Hi everyone,
> >
> > I have encountered an initially rather confusing problem in a piece of
> > code that attempted to symmetrize a matrix: `h += h.T`
> > The problem of course appears due to
Yes, I think it is guaranteed C order in the results.
On Mon Jul 27 14:05:01 2015 GMT+0200, Matthew Brett wrote:
> Hi,
>
> `np.nonzero` for a 2D array `A` returns:
>
> row_inds, col_inds = np.nonzero(A)
>
> I notice that `row_inds` appears to be sorted by value, and `col_inds`
> appears to be
