On Sat, 2013-01-12 at 00:26 +0100, Chao YUE wrote:
> Hi,
>
> I don't know how others think about this. Like you point out, one can
> use
> np.nonzero(a==np.max(a)) as a workaround.
>
> For the second point, in case I have an array:
> a = np.arange(24.).reshape(2,3,4)
>
> suppose I want to find
Hi,
I don't know how others think about this. Like you point out, one can use
np.nonzero(a==np.max(a)) as a workaround.
For the second point, in case I have an array:
a = np.arange(24.).reshape(2,3,4)
suppose I want to find the index for maximum value of each 2X3 array along
the 3rd dimension, w
On Thu, Jan 10, 2013 at 9:40 AM, Chao YUE wrote:
> Dear all,
>
> Are we going to consider returning the index of maximum value in an array
> easily
> without calling np.argmax and np.unravel_index consecutively?
This does seem like a good thing to support somehow. What would a good
interface look
np.unwrap was too slow, so I rolled by own (in c++).
I wanted to be able to handle the case of
unwrap (arg (x1) + arg (x2))
Here, phase can change by more than 2pi.
I came up with the following algorithm, any thoughts?
In the following, y is normally set to pi.
o points to output
i points to i
