Mark Janikas wrote:
> Thanks for the input! I wonder if I can resize my own record array? I.e.
> one call to truncate... Ill give it a go.
you should be able too, yes. Be careful though, you can't call resize()
if there are any other references to the array.
> But the resize works great as i
Thanks for the input! I wonder if I can resize my own record array? I.e. one
call to truncate... Ill give it a go. But the resize works great as it doesn't
make a copy:
In [12]: a = NUM.arange(10)
In [13]: id(a)
Out[13]: 190182896
In [14]: a.resize(5,)
In [15]: a
Out[15]: array([0, 1, 2, 3
On Fri, Oct 2, 2009 at 3:38 PM, Charles R Harris
wrote:
>
>
> On Fri, Oct 2, 2009 at 12:30 PM, wrote:
>>
>> On Fri, Oct 2, 2009 at 2:09 PM, Charles R Harris
>> wrote:
>> >
>> >
>> > On Fri, Oct 2, 2009 at 11:35 AM, Charles R Harris
>> > wrote:
>> >>
>> >>
>> >> On Fri, Oct 2, 2009 at 11:33 AM,
Is there any way to move the existing parts of this thread (i.e., not just
future posts, which of course is as simple as posting them there instead)
over to scipy-dev, where it really belongs?
DG
On Fri, Oct 2, 2009 at 12:56 PM, Pauli Virtanen wrote:
> to, 2009-10-01 kello 12:19 -0400, Ralf Gom
to, 2009-10-01 kello 12:19 -0400, Ralf Gommers kirjoitti:
> Sorry to ask again, but it would really be very useful to get those
> docstrings merged for both scipy and numpy.
[clip]
Numpy's new docstrings is are now in SVN too, for the most part. An
amazing amount of work was done during the summe
On Fri, Oct 2, 2009 at 12:30 PM, wrote:
> On Fri, Oct 2, 2009 at 2:09 PM, Charles R Harris
> wrote:
> >
> >
> > On Fri, Oct 2, 2009 at 11:35 AM, Charles R Harris
> > wrote:
> >>
> >>
> >> On Fri, Oct 2, 2009 at 11:33 AM, Charles R Harris
> >> wrote:
> >>>
> >>>
> >>> On Fri, Oct 2, 2009 at 11:
Mark Janikas wrote:
> So, do I use lists and
> append then create the arrays… Or do I fill up the pre-allocated “empty”
> arrays and slice off the ends? Thoughts? Thanks much…
Either will work. I think the decision would be based on how many Null
records you expect -- if it's a small fraction
Hello All,
I was hoping you could help me out with a simple little problem I am having:
I am reading data from a database that contains NULL values. There is more
than one field being read in with equal length, but if any of them are NULL in
a row, then I do NOT want to include it in my numpy
On Fri, Oct 2, 2009 at 2:09 PM, Charles R Harris
wrote:
>
>
> On Fri, Oct 2, 2009 at 11:35 AM, Charles R Harris
> wrote:
>>
>>
>> On Fri, Oct 2, 2009 at 11:33 AM, Charles R Harris
>> wrote:
>>>
>>>
>>> On Fri, Oct 2, 2009 at 11:30 AM, Charles R Harris
>>> wrote:
On Fri, Oct 2, 20
On Fri, Oct 2, 2009 at 11:35 AM, Charles R Harris wrote:
>
>
> On Fri, Oct 2, 2009 at 11:33 AM, Charles R Harris <
> charlesr.har...@gmail.com> wrote:
>
>>
>>
>> On Fri, Oct 2, 2009 at 11:30 AM, Charles R Harris <
>> charlesr.har...@gmail.com> wrote:
>>
>>>
>>>
>>> On Fri, Oct 2, 2009 at 11:08 AM
On Fri, Oct 2, 2009 at 11:33 AM, Charles R Harris wrote:
>
>
> On Fri, Oct 2, 2009 at 11:30 AM, Charles R Harris <
> charlesr.har...@gmail.com> wrote:
>
>>
>>
>> On Fri, Oct 2, 2009 at 11:08 AM, wrote:
>>
>>> Is there a way in numpy (or scipy) to get an infinite expansion for
>>> the inverse of
On Fri, Oct 2, 2009 at 11:30 AM, Charles R Harris wrote:
>
>
> On Fri, Oct 2, 2009 at 11:08 AM, wrote:
>
>> Is there a way in numpy (or scipy) to get an infinite expansion for
>> the inverse of a polynomial (for a finite number of terms)
>>
>> np.poly1d([ -0.8, 1])**(-1)
>>
>> application for ex
On Fri, Oct 2, 2009 at 11:08 AM, wrote:
> Is there a way in numpy (or scipy) to get an infinite expansion for
> the inverse of a polynomial (for a finite number of terms)
>
> np.poly1d([ -0.8, 1])**(-1)
>
> application for example the MA representation of an AR(1)
>
>
Hmm, I've been working on a
Is there a way in numpy (or scipy) to get an infinite expansion for
the inverse of a polynomial (for a finite number of terms)
np.poly1d([ -0.8, 1])**(-1)
application for example the MA representation of an AR(1)
and fractional powers
np.poly1d([ -1, 1])**0.5
this is useful for fractionally i
On 09/30/2009 12:44 PM, Skipper Seabold wrote:
> On Wed, Sep 30, 2009 at 12:56 PM, Bruce Southey wrote:
>
>> On 09/30/2009 10:22 AM, Skipper Seabold wrote:
>>
>>> On Tue, Sep 29, 2009 at 4:36 PM, Bruce Southeywrote:
>>>
>>>
>>>
Hi,
The first case just has to handle
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