On 06.08.2013 13:31, Richard Kearsley wrote:
On 06/08/13 04:02, Dennis Jacobfeuerborn wrote:
Since I determine the reason for the denied access in lua a way to do
it there would also help. I already tried "nginx.status = 403"
followed by a "nginx.exec('/reason1')" but while the right page is
di
On 06/08/13 04:02, Dennis Jacobfeuerborn wrote:
Since I determine the reason for the denied access in lua a way to do
it there would also help. I already tried "nginx.status = 403"
followed by a "nginx.exec('/reason1')" but while the right page is
display the status code returned gets reset to
On 06.08.2013 08:29, mex wrote:
let your app handle and deliver error-pages
See basically all I want to do is return a single static html file and
having to set up php/python/etc. just to serve this file seems like
overkill to me. This is pretty much the most simple case for a web
server to
let your app handle and deliver error-pages
Posted at Nginx Forum:
http://forum.nginx.org/read.php?2,241621,241626#msg-241626
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Hi,
I'm wondering how I can set a status code and still deliver a custom web
page? Specifically I want to use a status code of 403 Forbidden but
depending on the exact reason I want to display different custom error
pages for that case.
When I use the "return 403" directive I can no longer deli
