On 10/31/18 6:02 PM, Jeff Barnhill wrote:
> I'll follow this email with a new patch using ifacaddr6 instead of
> creating a new struct. I ended up using fib6_nh.nh_dev to get the net,
> instead of adding a back pointer to idev. It seems that idev was
> recently removed in lieu of this, so if this
I'll follow this email with a new patch using ifacaddr6 instead of
creating a new struct. I ended up using fib6_nh.nh_dev to get the net,
instead of adding a back pointer to idev. It seems that idev was
recently removed in lieu of this, so if this is incorrect, please let
me know. Hopefully, I got
From: David Ahern
Date: Tue, 30 Oct 2018 16:06:46 -0600
> or make the table per namespace.
This will increase namespace create/destroy cost, so I'd rather not
for something like this.
On 10/30/18 12:31 PM, David Miller wrote:
> From: Jeff Barnhill <0xeff...@gmail.com>
> Date: Tue, 30 Oct 2018 07:10:58 -0400
>
>> I originally started implementing it the way you suggested; however,
>> it seemed to complicate management of that structure because it isn't
>> currently using rcu. A
From: Jeff Barnhill <0xeff...@gmail.com>
Date: Tue, 30 Oct 2018 07:10:58 -0400
> I originally started implementing it the way you suggested; however,
> it seemed to complicate management of that structure because it isn't
> currently using rcu. Also, assuming that can be worked out, where
> would
I originally started implementing it the way you suggested; however,
it seemed to complicate management of that structure because it isn't
currently using rcu. Also, assuming that can be worked out, where
would I get the net from? Would I need to store a copy in ifcaddr6,
or is there some way to
From: Jeff Barnhill <0xeff...@gmail.com>
Date: Sun, 28 Oct 2018 01:51:59 +
> +struct ipv6_ac_addrlist {
> + struct in6_addr acal_addr;
> + possible_net_t acal_pnet;
> + refcount_t acal_users;
> + struct hlist_node acal_lst; /* inet6_acaddr_ls
icmp6_send() function is expensive on systems with a large number of
interfaces. Every time it’s called, it has to verify that the source
address does not correspond to an existing anycast address by looping
through every device and every anycast address on the device. This can
result in significa
