Re: [Mingw-w64-public] missing long double format in printf

2011-03-23 Thread James K Beard
o.com] Sent: Wednesday, March 23, 2011 3:09 AM To: Kai Tietz; mingw64 Subject: Re: [Mingw-w64-public] missing long double format in printf why does ll not work for int64_t and long long (I think) and __int64? this is quite noticeable. all my programs have to be #ifdef'd. #if defined(__

Re: [Mingw-w64-public] missing long double format in printf

2011-03-23 Thread Vincent Torri
e Vincent Torri > > -- > *From:* Kai Tietz > *To:* Jim Michaels > *Sent:* Tue, March 22, 2011 12:48:20 AM > *Subject:* Re: [Mingw-w64-public] missing long double format in printf > > 2011/3/22 Jim Michaels : > > if you are using __USE

Re: [Mingw-w64-public] missing long double format in printf

2011-03-23 Thread Jim Michaels
ul for someone making portable code. From: Kai Tietz To: Jim Michaels Sent: Tue, March 22, 2011 12:48:20 AM Subject: Re: [Mingw-w64-public] missing long double format in printf 2011/3/22 Jim Michaels : > if you are using __USE_MINGW_ANSI_STDIO can you still use %I64u?

Re: [Mingw-w64-public] missing long double format in printf

2011-02-24 Thread NightStrike
On Tue, Feb 22, 2011 at 3:54 AM, Kai Tietz wrote: > 2011/2/22 Jim Michaels : >> #include >> #include >> int main(void) { >>     int64_t n1=13000LL; >>     int64_t n2=1999888999256LL; >>     double >>     dnum=n1, >>     dden=n2, >>     dpercent=n1; >>     long double >>  

Re: [Mingw-w64-public] missing long double format in printf

2011-02-22 Thread Kai Tietz
2011/2/22 Jim Michaels : > #include > #include > int main(void) { >     int64_t n1=13000LL; >     int64_t n2=1999888999256LL; >     double >     dnum=n1, >     dden=n2, >     dpercent=n1; >     long double >     ldnum=n1, >     ldden=n2, >     ldpercent=n1; > >    

[Mingw-w64-public] missing long double format in printf

2011-02-21 Thread Jim Michaels
#include #include int main(void) { int64_t n1=13000LL; int64_t n2=1999888999256LL; double dnum=n1, dden=n2, dpercent=n1; long double ldnum=n1, ldden=n2, ldpercent=n1; dpercent/=dden; dpercent*=100; ldpercent/=ld