On Friday, December 9, 2016 9:41:51 AM PST Jason Ekstrand wrote:
> The formula we have used in the past is a trivial reduction from the
> definition by simply multiplying both the numerator and denominator of the
> formula by 2. However, multiplying by e^x, you can further reduce it.
> This allows
Unsurprisingly, the formula looks great to me :-).
I was actually wondering about accuracy. I believe the biggest issue
(both with the original formula and this one) is probably values around
zero - because that gets calculated as (~1 - 1) / 2 - so the closest
values to zero you can get (other than
The formula we have used in the past is a trivial reduction from the
definition by simply multiplying both the numerator and denominator of the
formula by 2. However, multiplying by e^x, you can further reduce it.
This allows us to get rid of one side of the clamp and two of exponential
functions
