On Fri, May 6, 2011 at 11:01 AM, Matt Turner wrote:
> 1/ln(2) is equivalent to log2(e), so define it as such.
>
> log2(e) = ln(e)/ln(2) = 1/ln(2)
>
> Worst of all, the definitions for M_LOG2E and ONE_DIV_LN2
> (right beside each other!) weren't the same.
>
> Reviewed-by: Alex Deucher
> Signed-off
1/ln(2) is equivalent to log2(e), so define it as such.
log2(e) = ln(e)/ln(2) = 1/ln(2)
Worst of all, the definitions for M_LOG2E and ONE_DIV_LN2
(right beside each other!) weren't the same.
Reviewed-by: Alex Deucher
Signed-off-by: Matt Turner
---
src/mesa/main/compiler.h |4
