On Wed, 3 Oct 2001 09:51:35 +0100
Kiat Huang <[EMAIL PROTECTED]> wrote:
> On Tue, Oct 02, 2001 at 11:43:32AM -0700, J C Lawrence wrote:
>> On Tue, 2 Oct 2001 10:16:22 -0700 Kiat Huang <[EMAIL PROTECTED]>
>> wrote:
>>> Hi, Is there a way through the web interface or other means (say
>>> as the ma
On Tue, Oct 02, 2001 at 11:43:32AM -0700, J C Lawrence wrote:
> On Tue, 2 Oct 2001 10:16:22 -0700
> Kiat Huang <[EMAIL PROTECTED]> wrote:
>
> > Hi, Is there a way through the web interface or other means (say
> > as the mailman admin, or a user not root (linux)) that can list
> > all the lists
ECTED]>
To: "Kiat Huang" <[EMAIL PROTECTED]>
Cc: <[EMAIL PROTECTED]>
Sent: Tuesday, October 02, 2001 2:09 PM
Subject: Re: [Mailman-Users] getting a subscriber's lists
> On 02 October 2001, Kiat Huang said:
> > Is there a way through the web interface or other
On Tue, 2 Oct 2001 10:16:22 -0700
Kiat Huang <[EMAIL PROTECTED]> wrote:
> Hi, Is there a way through the web interface or other means (say
> as the mailman admin, or a user not root (linux)) that can list
> all the lists a given user is subscribed to?
There's a button to that effect on every l
On 02 October 2001, Kiat Huang said:
> Is there a way through the web interface or other means (say as the
> mailman admin, or a user not root (linux)) that can list all the lists a
> given user is subscribed to?
This works for me as root (using bash):
cd ~mailman
for list in lists/* ; do
Hi,
Is there a way through the web interface or other means (say as the
mailman admin, or a user not root (linux)) that can list all the lists a
given user is subscribed to?
Cheers,
Kiat
--
Kiat Huang direc
