o create a HTTP server for RTSP-over-HTTP tunneling.
// Try first with the default HTTP port (80), and then with the
alternative HTTP
// port number (8000).
Thanks for your help as always!
Ken Seo
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Thanks Ross for your quick reply!
Regards,
Ken
2008/8/20 Ross Finlayson <[EMAIL PROTECTED]>
> Now the client can make an RTSP request just fine and start playing the
> stream. However, the RTCP packets from the client to the server get lost and
> as a result, the server stops the streaming wit
he client gets the address from the RTCP packets
sent from the server, then use it as destination.
Any idea, comment is greatly appreciated,
Regards,
Ken Seo
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I was just wondering, isn't fRTCPInterface supposed to be
fRTPInterface, since it is actually an instance of RTPInterface,
I know that I don't fully understand live555 code at the moment, so, if what
I explained above does not make any sense to you then please let me know,
Best Reg
Hi Ross,
I apologize if my post sounded like complaining, but I didn't intend
to do that.., I actually very much appreciate sharing your code.
My name is Ken Seo, working at Research In Motion Canada, the reason I
used my gmail is because I'm personally doing some research on
RTP/RTS
cause of a
single client failure, Is there any way I can manually flush the
socket when I get the error 10038 instead of terminating the server?
Best Regards,
Ken Seo
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l32.dll!7c816fd7()
[Frames below may be incorrect and/or missing, no symbols loaded for
kernel32.dll]
Any suggestions or ideas are greatly appreciated,
Best Regards,
Ken S.
On Tue, Apr 8, 2008 at 7:28 PM, Ken Seo <[EMAIL PROTECTED]> wrote:
> Hi, Ross,
>
> Th
Hi, Ross,
Thank you for your reply,
if "doGetNextFrame()" returns immediately, I'm not quite sure how it
would work, the following is my understanding of RTP cycle,
RTSPServer
- upon start playing - calls GetNextFrame() -> calls doGetNextFrame()
-> calls afterGetting() -> sends packets all that
ing, live555 is single threaded, how else do I implement
blocking ?? and who's responsible to call GetNextFrame()?
Regards,
Ken Seo
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