> Can you please give me a head start on how to correctly calculate the
> presentation times? For instance, do I need to have the same time value for
> an audio frame and a video frame that should be played together?
Yes.
> Should I use a shared presentation time variable for both streams?
I’
Hello Ross,
Thanks for the kind and fast reply.
Can you please give me a head start on how to correctly calculate the
presentation times? For instance, do I need to have the same time value for an
audio frame and a video frame that should be played together? Should I use a
shared presentation t
> What am I doing wrong? I’ve read a lot about it and it seems my presentation
> times are not ok, but how can I calculate them properly?
Yes, the problem seems to be the presentation times (i.e., the values of the
“fPresentationTime” member variable) that you’re setting for both your audio
and
It wasn’t totally clear from your message, but you seem to be implying that
there is a NAT between your server and your client - with your server on the
public Internet, and your client in a private IP address space (i.e., behind a
NAT).
In general, you *cannot* expect RTP/RTCP/RTSP streaming t
Hi Daniel,
First, you should ensure your time between audio and video are sync.
Then, just put struct timval into fPresentation time(need sec and usec).
Second, ensure your audio duration time is ok, you could refer ATDS source code.
I hope this may help you. Thanks?.
regards, eric, 11/04
Hello there,
I've been working on your library for a while now, in order to implement a RTSP
server, streaming live audio and video.
The audio and video packets are received via TCP from another service, each
type of packet (audio\video) to another socket.
What I did was creating a new sub-classe
Hi Ross,
Thanks for the earlier reply.
Can you please examine my following observation and provide your kind feedback
on this.
our server is a public server and for this I am using testRTSPClient on my
local machine. I observed the RTCP packets on wireshark at both client and
server end. Wha
