sungwy commented on issue #2030:
URL:
https://github.com/apache/iceberg-python/issues/2030#issuecomment-2903096164
Hi @DavidEscott thanks for raising this issue! As you pointed out this has
been a frequently discussed issue on PyIceberg, and there's still the original
open issue that track
DavidEscott commented on issue #2030:
URL:
https://github.com/apache/iceberg-python/issues/2030#issuecomment-2902490361
There seem to be two existing issues related to this, but both are closed.
[#1797] and [#1100]. I've adopted the approach from 1100, and it does work, but
I certainly dis
DavidEscott commented on issue #2030:
URL:
https://github.com/apache/iceberg-python/issues/2030#issuecomment-2902134199
Not in my use-case, because I also want to specify the `PartitionSpec` for
`create_table`. From what I can tell the signature of `catalog.create_table`
doesn't work at pr
jayceslesar commented on issue #2030:
URL:
https://github.com/apache/iceberg-python/issues/2030#issuecomment-2899052207
Does the following not work?
```py
import pyarrow as pa
schema = pa.schema(
[
pa.field("foo", pa.string(), nullable=True),
pa.
DavidEscott opened a new issue, #2030:
URL: https://github.com/apache/iceberg-python/issues/2030
### Apache Iceberg version
0.9.0
### Please describe the bug 🐞
I can't figure out how one is actually expected to create a table from a
pyarrow schema.
For this use ca
