On 8/28/25 9:48 AM, Sirui Mu wrote:
Hello,
The following minimum reproducer would miscompile with vanilla gcc:
extern int x[10], y[10];
bool g();
void f() { 0[g() ? x : y] = 1; }
gcc would mistakenly treat the subexpression (g() ? x : y) as a prvalue and
move that array to stack. The
Hello,
The following minimum reproducer would miscompile with vanilla gcc:
extern int x[10], y[10];
bool g();
void f() { 0[g() ? x : y] = 1; }
gcc would mistakenly treat the subexpression (g() ? x : y) as a prvalue and
move that array to stack. The following assignment would then write to
