On 04/10/2013 09:31 AM, Jakub Jelinek wrote:
Hi!
As f1 in the testcase shows, applying distributive law in extract_muldiv_1
isn't safe if overflow behavior isn't defined, if we have
(op0 + c1) * c2
and the type is signed, we can't just try to fold that to
op0 * c2 + (c1 * c2)
even when we know t
Hi!
As f1 in the testcase shows, applying distributive law in extract_muldiv_1
isn't safe if overflow behavior isn't defined, if we have
(op0 + c1) * c2
and the type is signed, we can't just try to fold that to
op0 * c2 + (c1 * c2)
even when we know that c1*c2 doesn't overflow, because op0 * c2
mi
