gcc-4.7.1 build system question : why is "make bootstrap" with configure option '--enable-languages=c' building the C++ compiler ?

2012-07-08 Thread Jason Vas Dias
suggest why making a "bootstrap" "C" "--enable-languages=c" compiler should then go on to build "C++" ? I'm pretty sure the above error would not have occurred without the kernel lock-up and interruption, but nevertheless, I didn't ask the gcc build system to build C++ yet, so why did it do so ? Any ideas / comments would be much appreciated , Jason Vas Dias (a Software Engineer)

Re: gcc-4.7.1 build system question : why is "make bootstrap" with configure option '--enable-languages=c' building the C++ compiler ?

2012-07-08 Thread Jason Vas Dias
compiler and libstdc++ ? Thanks & Regards, Jason On Sun, Jul 8, 2012 at 4:06 PM, Jason Vas Dias wrote: > Hi - I've been regularly building gcc for nearly two decades, and now > attempting to build a bootstrap > "C" only gcc-4.7.1 sufficient only to build binutils (my in

bug ? : -Wpedantic -Wconversion 'short a=1; a-=1;' complaint

2018-04-23 Thread Jason Vas Dias
I really do not think a '-Wpedantic -Wconversion' warning should be generated for the following code, but it is (with GCC 6.4.1 and 7.3.1 on RHEL-7.5 Linux) : $ echo ' typedef unsigned short U16_t; static void f(void) { U16_t a = 1; a-=1; }' > t.C; $ g++ -std=c++14 -Wall -Wextra -pedant

Re: bug ? : -Wpedantic -Wconversion 'short a=1; a-=1;' complaint

2018-05-16 Thread Jason Vas Dias
Great thanks for your informative response, Jim! : RE: On 23/04/2018, Jim Wilson wrote: > On 04/23/2018 07:11 AM, Jason Vas Dias wrote: >> >> I really do not think a '-Wpedantic -Wconversion' warning should >> be generated for the following code, but it is >>