https://gcc.gnu.org/bugzilla/show_bug.cgi?id=35307
Segher Boessenkool changed:
What|Removed |Added
Status|NEW |RESOLVED
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--- Comment #3 from segher at kernel dot crashing dot org 2008-02-26 16:16
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> > Not equivalent in the presence of overflow.
>
> You mean defined overflow :).
No, I mean overflow.
Let's assume int is 16-bit (just to keep the numbers smallish);
now take i=1, j=1000, k=1000. i/j/k i
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rguenth at gcc dot gnu dot org changed:
What|Removed |Added
Status|UNCONFIRMED |NEW
Ever Confirmed|0 |1
Last reconfi
--- Comment #2 from pinskia at gcc dot gnu dot org 2008-02-23 20:00 ---
(In reply to comment #1)
> Not equivalent in the presence of overflow.
You mean defined overflow :).
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pinskia at gcc dot gnu dot org changed:
What|Removed |Added
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--- Comment #1 from segher at kernel dot crashing dot org 2008-02-23 19:57
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Not equivalent in the presence of overflow.
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http://gcc.gnu.org/bugzilla/show_bug.cgi?id=35307
