http://gcc.gnu.org/bugzilla/show_bug.cgi?id=60978
--- Comment #5 from Manuel López-Ibáñez ---
I think it should not warn for anonymous enums. The point of the warning is
that using different enum types in a conditional expression is often some
programming mistake. But in the case of anonymous enu
http://gcc.gnu.org/bugzilla/show_bug.cgi?id=60978
--- Comment #4 from Manuel López-Ibáñez ---
(In reply to Manuel López-Ibáñez from comment #3)
> I don't even understand what this code is trying to warn about:
>
> if (TREE_CODE (arg2_type) == ENUMERAL_TYPE
> && TREE_CODE (arg3_type
http://gcc.gnu.org/bugzilla/show_bug.cgi?id=60978
Manuel López-Ibáñez changed:
What|Removed |Added
CC||manu at gcc dot gnu.org
--- Comment
http://gcc.gnu.org/bugzilla/show_bug.cgi?id=60978
--- Comment #2 from Paul Pluzhnikov ---
(In reply to Andrew Pinski from comment #1)
> This is documented to do this even in 4.8
> (http://gcc.gnu.org/onlinedocs/gcc-4.8.2/gcc/Warning-Options.html):
> In C++ enumeral mismatches in conditional expr
http://gcc.gnu.org/bugzilla/show_bug.cgi?id=60978
--- Comment #1 from Andrew Pinski ---
This is documented to do this even in 4.8
(http://gcc.gnu.org/onlinedocs/gcc-4.8.2/gcc/Warning-Options.html):
In C++ enumeral mismatches in conditional expressions are also diagnosed and
the warning is enable
