--- Comment #3 from pinskia at gcc dot gnu dot org 2005-12-02 21:14 ---
(In reply to comment #2)
> I really don't think that the reply addresses the question. If a function
> returns an object it has to call a copy constructor. This code compiles if the
> copy constructor is declared as
--- Comment #2 from richard at rggibbs dot com 2005-12-02 21:11 ---
I really don't think that the reply addresses the question. If a function
returns an object it has to call a copy constructor. This code compiles if the
copy constructor is declared as
t1(const t1& tr);
but fails if de
--- Comment #1 from pinskia at gcc dot gnu dot org 2005-12-02 20:53 ---
This is expected and how C++ works.
t1(t1& tr);
is a copy constructor which only takes references which means it only takes
lvalues.
t1 dosomething(const t1& v) const;
That means it returns a variable and calling tha
