Behalf Of
Steven Bosscher
Sent: Thursday, February 09, 2006 1:31 PM
To: gcc@gcc.gnu.org
Cc: rajagopal, dwarak
Subject: Re: cmov for stores
On Thursday 09 February 2006 20:04, rajagopal, dwarak wrote:
> The fact here is that in this case, A[k] will never trap because the
> A[k] is already bee
On Thursday 09 February 2006 20:04, rajagopal, dwarak wrote:
> The fact here is that in this case, A[k] will never trap because the
> A[k] is already been written once along the path from Entry to the "A[k]
> = g". So it is safe to convert it to a cmov statement.
But GCC doesn't know that this mem
int cmov(int* A ,int B ,int C ,int* D ,int* E ,int F ,int g)
{
int k,f;
for (k = 1; k <= 1000; k++) {
A[k] = B+C;
g = D[k-1] + E[k-1];
if (g > A[k]) A[k]=g; /* This is not converted to cmov*/
f += g;
}
return f;
}
In the above code, the if-then statement is not conve
