Quoting Jakub Jelinek :
On Sun, Mar 06, 2011 at 09:56:52AM +0100, Marc Glisse wrote:
>uintmax_t is the largest of the standard unsigned C types, so it
cannot be larger than unsigned long long.
That's a gcc property then. The C99 standard only guarantees that
uintmax_t is at least as large a
On Sun, Mar 06, 2011 at 09:56:52AM +0100, Marc Glisse wrote:
> >uintmax_t is the largest of the standard unsigned C types, so it cannot be
> >larger than unsigned long long.
>
> That's a gcc property then. The C99 standard only guarantees that
> uintmax_t is at least as large as unsigned long lon
Coucou FX,
On Sat, 5 Mar 2011, FX wrote:
uintmax_t is the largest of the standard unsigned C types, so it cannot be
larger than unsigned long long.
That's a gcc property then. The C99 standard only guarantees that
uintmax_t is at least as large as unsigned long long, but it is allowed to
Salut Marc !
> We have a variable of type uintmax_t and want to count the leading zeros. Can
> we just call __builtin_clzll on it?
Yes.
> In particular, can uintmax_t be larger than unsigned long long in gcc?
uintmax_t is the largest of the standard unsigned C types, so it cannot be
larger th
Hello,
the following question came up for a libstdc++ patch. We have a variable
of type uintmax_t and want to count the leading zeros. Can we just call
__builtin_clzll on it?
In particular, can uintmax_t be larger than unsigned long long in gcc? Is
__builtin_clzll available on all platforms?
