Thanks Jon,
Can anyone throw more light on this.
Regards,
Sanjiv
--- Jonathan Wakely <[EMAIL PROTECTED]> wrote:
> On Fri, Feb 11, 2005 at 06:08:55AM -0800, san san
> wrote:
>
> > Hi Jon,
> >
> > Thanks again for replying. Let me clarify my
> problem:
> &
there is any other way by which i can figure out
that.
I hope i am clear this time :).
Regards,
San
--- Jonathan Wakely <[EMAIL PROTECTED]> wrote:
> On Fri, Feb 11, 2005 at 05:44:52AM -0800, san san
> wrote:
>
> > Hi Jonathan & Everyone,
>
> Hello again San
Hi Jonathan & Everyone,
Thanks for your reply. Yes, as you pointed out, it
will create only 2 temporaries as below:
X a(1);
sub r3, fp, #16
mov r0, r3
mov r1, #1
bl X::X[in-charge](int)
a = f(a);
sub r3, fp, #24
sub r2, fp,