Version: GCC 11.2 (msys2 mingw-w64 X86_64)
When a macro have more than one arguments, and u call it with no argument,
gcc will compliant with " only 1 given" instead of " 0 given"
Demo code:
#define TEST(x,y) test(x,y)
int main() {
int x=TEST();
}:
Error message:
F:/test.cpp:4:20: error: macro "
I use "gcc -finput-charset=utf-8 -fexec-charset=gb2312" to compile utf-8
encoding source files under windows. Most of the time it works well, but
when the source file contains some characters such as "—", gcc will fail
and the error message is: "[Error] converting to execution character set:
Ille
