there are much faster ways...just a little more
intricate.
Nando
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Open WebMail Project (http://openwebmail.org)
-- Original Message ---
From: Fernando Cabral
To: mailing list for gambas users
Sent: Sat, 1 Jul 2017 00:18:42 -0300
Subject: Re: [Gambas-user] I need a hint on
I thank you guys for the hints on counting and eliminating duplicates. In
the end, I resorted to something that is very simple and does the trick in
three steps. In the first step I sort the array.
In the second step I count the number of occurrences and prepend it to the
word itself (with a separa
Just for curiosity, on my computer, my function (double) processes 10
million strings (first and last name) in about 3 seconds.
Very naif measurement using Timers and a limited number of names and
surnames eg Willy Weber has come up 11051 times
To demonstrate the goodness of Tobias' arguments, abo
Sorry Tobias,
other explanations are not necessary.
I would not be able to understand :-(
I accept what you already explained to me as a dogma and I will try to put
it into practice by copying your code :-).
Thanks again.
Gianluigi
2017-06-30 17:44 GMT+02:00 Gianluigi :
>
> 2017-06-30 17:21 GMT
2017-06-30 17:21 GMT+02:00 Tobias Boege :
>
> I wouldn't say there is anything *wrong* with it, but it also has quadratic
> worst-case running time. You use String[].Push() which is just another name
> for String[].Add(). Adding an element to an array (the straightforward way)
> is done by extendi
On Fri, 30 Jun 2017, Gianluigi wrote:
> What was wrong in my example which meant this?
>
> Public Sub Main()
>
> Dim sSort As String[] = ["A", "B", "B", "B", "C", "D", "D", "E", "E",
> "E", "E", "F"]
> Dim s As String
>
> For Each s In ReturnArrays(sSort, 0)
> Print s
> Next
> For
What was wrong in my example which meant this?
Public Sub Main()
Dim sSort As String[] = ["A", "B", "B", "B", "C", "D", "D", "E", "E",
"E", "E", "F"]
Dim s As String
For Each s In ReturnArrays(sSort, 0)
Print s
Next
For Each s In ReturnArrays(sSort, -1)
Print s
Next
End
Pri
On Fri, 30 Jun 2017, Fernando Cabral wrote:
> 2017-06-30 7:44 GMT-03:00 Fabien Bodard :
>
> > The best way is the nando one ... at least for gambas.
> >
> > As you have not to matter about what is the index value or the order,
> > the walk ahead option is the better.
> >
> >
> > Then Fernando ...
On 30/06/17 08:20, Fernando Cabral wrote:
> 2017-06-30 7:44 GMT-03:00 Fabien Bodard :
>> The best way is the nando one ... at least for gambas.
>> As you have not to matter about what is the index value or the order,
>> the walk ahead option is the better.
>> Then Fernando ... for big, big things..
; > Next
> >> >
> >> > 'if you want it sorted, do it here
> >> > Return z
> >> >
> >> > END
> >> >
> >> > ' - - - - -
> >> > use it this way:
> >> >
> >> > myArray = Remo
> Return z
>> >
>> > END
>> >
>> > ' - - - - -
>> > use it this way:
>> >
>> > myArray = RemoveMultiple(myArray)
>> > 'the z array is now myArray.
>> > 'the original array is destroyed because there a
mple would be:
> > > >
> > > > You have your array with data
> > > > You create a new empty array.
> > > >
> > > > Loop through each item in your array with data
> > > > If it's not in the new array, then add it.
>
s destroyed because there are no references.
>
>
>
> --
> Open WebMail Project (http://openwebmail.org)
>
>
> -- Original Message ---
> From: Gianluigi
> To: mailing list for gambas users
> Sent: Tue, 27 Jun 2017 16:52:48 +0200
> Subject: Re: [Gambas-user
age -------
> From: Gianluigi
> To: mailing list for gambas users
> Sent: Tue, 27 Jun 2017 16:52:48 +0200
> Subject: Re: [Gambas-user] I need a hint on how to deleted duplicate items
> in a array
>
> > My two cents.
> >
> > Public Sub Main()
> >
>
On Tue, 27 Jun 2017, Fernando Cabral wrote:
> So, my question is basically if Gambas has some built in method do
> eliminate duplicates.
> The reason I am asking this is because I am new to Gambas, so I have found
> myself coding
> things that were not needed. For instance, I coded some functions t
2017-06-27 11:29 GMT-03:00 Tobias Boege :
>
> Your first sentence is a bit confusing. First you say that your array is
> sorted but then you say that duplicates may be scattered across the array.
>
You are right. My fault. The array is sorted. What I meant by scattered was
that
pairs, duples, trip
Message ---
From: Gianluigi
To: mailing list for gambas users
Sent: Tue, 27 Jun 2017 16:52:48 +0200
Subject: Re: [Gambas-user] I need a hint on how to deleted duplicate items in a
array
> My two cents.
>
> Public Sub Main()
>
> Dim sSort As String[] = ["A",
[]
>
> Dim x as Integer
> Dim z as NEW STRING[]
>
> For x = 1 to a.count()
> if z.Find(a) = 0 Then z.Add(a[x])
> Next
>
> Return z
>
> END
>
> -Nando (Canada)
>
>
>
>
> --
> Open WebMail Project (http://openwebmail.org)
>
>
From: Hans Lehmann
To: gambas-user@lists.sourceforge.net
Sent: Tue, 27 Jun 2017 15:51:19 +0200
Subject: Re: [Gambas-user] I need a hint on how to deleted duplicate items in a
array
> Hello,
>
> loo
On Tue, 27 Jun 2017, Fernando Cabral wrote:
> Hi
>
> I have a sorted array that may contain several repeated items scattered all
> over.
>
> I have to do two different things at different times:
> a) Eliminate the duplicates leaving a single specimen from each repeated
> item;
> b) Eliminate the
Hello,
look here:
8<-
Public Function RemoveMultiple(aStringListe As String[]) As String[]
Dim iCount As Integer
Dim iIndex As Integer
Dim sElement As String
iIndex = 0 ' Initialisierung NICHT notwen
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