I get this when I run this code
1.1
1.1
1.16
1.2
1.2
1.3
1.35
1.4
1.5
1.6
Notice how it's listing "1.1" and "1.2" twice, this is because of the entries
"1.1" and "1.10" These would in fact need to be different
I guess there really is no easy way other than splitting each version string
into an
Dim arf As New Float[]
Dim f As Float
Dim s As String
For Each s In Split("1.2,1.4,1.6,1.10,1.16,1.20,1.35,1.5,1.3,1.1")
arf.add(s)
Next
arf.Sort
For Each f In arf
Print f
Next
Regards,
Fabien Bodard
--
Just brainstorming here, but if you add format the float in a 2 decimal
string then replace "." with ""
and reconvert the string to an integer you might be able to get the right
kind of comparison results.
like 2.05 and 2.10 would turn into 205 and 210 In which case using max
would give you the la
On Wednesday 25 March 2009 13:54, M0E.lnx wrote:
> I guess I would have thoutht there was something that could analize
> something like "2.12" and "2.5" as floats and see which one is the
> largest of the 2
Well, the problem with that is that 2.5 really is the larger of the two if
you treat them
True... It's impossible to catch all of them. Not all developers stick to the
standards.. I understand.
FWIW, I've stated a class that takes the 2 strings and then splits them at the
separator (".") After that it analizes each object in the array and determines
which one of the two arguments is
On Wednesday 25 March 2009 13:19, M0E.lnx wrote:
> I'm not dealing with my own version numbering here... I'm trying to
> analize all versioning schemes if at all possible.
It's not possible. 2.5 and 2.10 in the Gambas numbering scheme mean
different things than 2.10 and 2.5 in some other develop
Yeah... and like I said, this works, but
I'm not dealing with my own version numbering here... I'm trying to analize all
versioning schemes if at all possible.
I guess I could split the version string into an array and figure out manually
from there... But I was kind of hoping not to do that. ;
The replace(".","") thing works, but it rus into problems with you get to
something like 1.3b vs 1.3c
Some developers have a different way of numbering their releases.
--
___
G
Hi all
This is the way I did it:
First, I've setup an asynchronous httpclient.
PUBLIC SUB _getVer_Finished()
DIM myVersion, verUpdate AS Integer
DIM sMyVer AS String = "1" & Replace(Application.Version, ".", "")
ver = "1" & Replace(ver, ".", "")
myVersion = CInt(sMyVer)
On Wednesday 25 March 2009 11:29, Ron wrote:
> > I guess, in these cases, you can use the Val() function.
> Do a replace to remove the . then 12 is less(older) then 135.
That only works if all the versions are part of the same major release. 21
is less than 135 too...
In Perl, I would do someth
Laurent Carlier schreef:
> Le mercredi 25 mars 2009 16:07:11 M0E.lnx, vous avez écrit :
>> I need a way to logically analize version numbers in gambas.
>>
>> For instance, I have a list of available versions of the same program,
>> let's say the list is
>>
>> 1.2
>> 1.4
>> 1.6
>> 1.10
>> 1.16
>> 1.
Le mercredi 25 mars 2009 16:07:11 M0E.lnx, vous avez écrit :
> I need a way to logically analize version numbers in gambas.
>
> For instance, I have a list of available versions of the same program,
> let's say the list is
>
> 1.2
> 1.4
> 1.6
> 1.10
> 1.16
> 1.20
> 1.35
> 1.5
> 1.3
> 1.1
>
> These
I need a way to logically analize version numbers in gambas.
For instance, I have a list of available versions of the same program, let's
say the list is
1.2
1.4
1.6
1.10
1.16
1.20
1.35
1.5
1.3
1.1
These are of course in no particular order. A human knows that out of all of
these, version 1.35
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