Thank you guys. The first suggestion worked.
On Apr 30, 2009 3:24 PM, "Simonart Dominique"
wrote:
Frank Cox a écrit :
> On Thu, 30 Apr 2009 14:00:06 -0500 > M0E Lnx wrote: > > >> I need a way to
take a number, say an...
A = N mod 250
N = N - A
if A > 125 then N += 250
In this case N=125 would
Frank Cox a écrit :
> On Thu, 30 Apr 2009 14:00:06 -0500
> M0E Lnx wrote:
>
>
>> I need a way to take a number, say an integer and round it up to the
>> nearest increment of 250. This may imply decreasing or increasing the
>> number.
>
> Divide the number by 250.
>
> If the result is > x.5 then
On Thu, 30 Apr 2009 14:00:06 -0500
M0E Lnx wrote:
> I need a way to take a number, say an integer and round it up to the
> nearest increment of 250. This may imply decreasing or increasing the
> number.
Divide the number by 250.
If the result is > x.5 then (x+1)*250
If the result is < x.5 the
This dilema is running circles around my head... I need help
I need a way to take a number, say an integer and round it up to the
nearest increment of 250. This may imply decreasing or increasing the
number.
For instance
input = 400
I need my app to round up to 500
input = 550
I need my app to ro
