Le 07/11/2014 09:03, roberto a écrit :
> Hi Benoît (it is always a pleasure to read you in mailing list)
>
> we have eg 3 cases:
> 1°->
> "Content-Type: text/plain; charset="iso-8859-1"
>
> print hpart.ContentType
> output-> "text/plain"
> print hpart.Header["Content-type"]
> output-> text/plain; c
Hi Benoît (it is always a pleasure to read you in mailing list)
we have eg 3 cases:
1°->
"Content-Type: text/plain; charset="iso-8859-1"
print hpart.ContentType
output-> "text/plain"
print hpart.Header["Content-type"]
output-> text/plain; charset="iso-8859-1"
2°->
"Content-Type: text/plain; char
Le 06/11/2014 13:20, roberto a écrit :
> Thanks Jorge for you fast reply
>
> I have tried with:
>
>s = hPart.Headers["content-type"]
> If InStr(s, "charset") > 0 Then
> bla bla bla (estrapolate "charset" content )
> endif
>
> but is not an excellent solution
>
AFA
Thanks Jorge for you fast reply
I have tried with:
s = hPart.Headers["content-type"]
If InStr(s, "charset") > 0 Then
bla bla bla (estrapolate "charset" content )
endif
but is not an excellent solution
Il 06/11/2014 12:24, Jorge Carrión ha scritto:
> I use this cod
I use this code in the EMail function to set the mime. I'm not very sure if
this is what you are asking for:
For Each fich In aAttached
Exec ["file", "-bi", fich] To mime
mime = Left(mime, InStr(mime, ";") - 1)
fname = Right(fich, - RInStr(fich, "/"))
Dear All,
there is a method to get the charset of a mimepart ( eg.
part.ContentType = "plain/text" )?
Best Regards
Gambas 3.6
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