On Sun, 28 May 2017, Fernando Cabral wrote:
> In the piece of code bellow, RegExp.Replace will never return.
>
> Sentencas[i] = "Test string."
> Print "Before replacing"
> Sentencas[i] = RegExp.Replace(Sentencas[i], "[.:!?;]*[ ]*?\n*?", "",
> RegExp.UTF8)
> Print "After replacing"
>
> It beats me
In the piece of code bellow, RegExp.Replace will never return.
Sentencas[i] = "Test string."
Print "Before replacing"
Sentencas[i] = RegExp.Replace(Sentencas[i], "[.:!?;]*[ ]*?\n*?", "",
RegExp.UTF8)
Print "After replacing"
It beats me, because what it should do is very simple: optionally find on