Am Dienstag, den 04.08.2015, 16:33 -0400 schrieb Martin McGlensey:
> Charlie,
>
>
>
> Thanks for the response. I thought it might be a bug as the routine worked
> before. I do not think the work around will work as I want it to. My
> understanding is that a datasource built on a query cannot be
Charlie,
Thanks for the response. I thought it might be a bug as the routine worked
before. I do not think the work around will work as I want it to. My
understanding is that a datasource built on a query cannot be edited and
updated. I need to change the value of the key based on the user sele
Am Dienstag, den 04.08.2015, 21:25 +0200 schrieb Adrien Prokopowicz:
> Le Tue, 04 Aug 2015 19:07:36 +0200, Martin McGlensey
> a écrit:
>
> > Charlie,
> >
> >
> > Here is the form and the data table. You will have to recode the
> > connection
> > for the datasources as well as using an integer
Am Dienstag, den 04.08.2015, 13:07 -0400 schrieb Martin McGlensey:
> Charlie,
>
>
>
> Here is the form and the data table. You will have to recode the connection
> for the datasources as well as using an integer (1-200) for
> frmEntry.DataControl.Value.
>
>
>
> Regards,
>
> Marty
>
Salut
Le Tue, 04 Aug 2015 19:07:36 +0200, Martin McGlensey
a écrit:
> Charlie,
>
>
> Here is the form and the data table. You will have to recode the
> connection
> for the datasources as well as using an integer (1-200) for
> frmEntry.DataControl.Value.
>
>
> Regards,
>
> Marty
>
This should be f
Charlie,
Here is the form and the data table. You will have to recode the connection
for the datasources as well as using an integer (1-200) for
frmEntry.DataControl.Value.
Regards,
Marty
Form_Test-0.0.1.tar.gz
Description: GNU Zip compressed data
tblparcel_numbers.sql
Description: Bi
Am Dienstag, den 04.08.2015, 09:32 -0400 schrieb Martin McGlensey:
> Charlie,
>
>
>
> Did as you suggested. Created new form with two datasources and two dataview
> controls. Copied the relevant code into new form. Same error as with the
> original form. When the original form was created the c
Charlie,
Did as you suggested. Created new form with two datasources and two dataview
controls. Copied the relevant code into new form. Same error as with the
original form. When the original form was created the code did work. I think
it was back in Gambas 3.6 or so. Maybe it has something to
Some more information. If I create a Result object using the syntax below
the SQL query executes properly.
Dim sSQL as String = Null
Dim hRows as Result = Null
sSQL = "SELECT tblparcel_numbers.Key FROM tblparcel_numbers WHERE
tblparcel_numbers.Key <> " & frmEntry.DataControl10.Value
hRo
Le Sun, 02 Aug 2015 22:07:35 +0200, Martin McGlensey
a écrit:
> Hello,
>
>
> I have the code below in my MySQL/Mariadb project.
>
>
> DataSource1.Connection = modMain.$Con
>
> DataSource1.Table = "tblparcel_numbers"
>
> DataSource1.Filter = db.Subst("tblparcel_numbers.Key = &1",
Hello,
I have the code below in my MySQL/Mariadb project.
DataSource1.Connection = modMain.$Con
DataSource1.Table = "tblparcel_numbers"
DataSource1.Filter = db.Subst("tblparcel_numbers.Key = &1",
frmEntry.DataControl10.Value)
DataSource1.Sort = "Parcel_No"
DataV
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