Re: Converting const char (&name)[N] to nsACString

2017-07-21 Thread Boris Zbarsky
On 7/21/17 9:44 AM, nmago wrote: Yes, I needed nsACString copy of data to use it as nsACString argument for other function. Assuming "cname" is a char[N] or char*, you should be able to do: nsCString str(cname, N); This will make a copy of the first N bytes of cname and add a null-termina

Re: Converting const char (&name)[N] to nsACString

2017-07-21 Thread nmago
воскресенье, 9 июля 2017 г., 4:10:43 UTC+3 пользователь Boris Zbarsky написал: > On 7/5/17 5:41 AM, nmago wrote: > > char* cname = new char[N]; > > memcpy(cname, &name, N); > > nsACString strName(cname, N, 0); > > This copies the data twice, and leaks it once, as far as I can tell. > > What, exac

Re: Converting const char (&name)[N] to nsACString

2017-07-08 Thread Boris Zbarsky
On 7/5/17 5:41 AM, nmago wrote: char* cname = new char[N]; memcpy(cname, &name, N); nsACString strName(cname, N, 0); This copies the data twice, and leaks it once, as far as I can tell. What, exactly, are you trying to accomplish? For example, do you need an nsACString that has a copy of you

Re: Converting const char (&name)[N] to nsACString

2017-07-05 Thread James Cheng
Why do you need a copy? Could you just cast the name to char*? 2017年7月5日 下午5:45，"nmago" 寫道： Thank you, Honza Bambas and smaug! Found solution: char* cname = new char[N]; memcpy(cname, &name, N); nsACString strName(cname, N, 0); ___ dev-platform mailin

Re: Converting const char (&name)[N] to nsACString

2017-07-05 Thread nmago
Thank you, Honza Bambas and smaug! Found solution: char* cname = new char[N]; memcpy(cname, &name, N); nsACString strName(cname, N, 0); ___ dev-platform mailing list dev-platform@lists.mozilla.org https://lists.mozilla.org/listinfo/dev-platform

Re: Converting const char (&name)[N] to nsACString

2017-07-04 Thread smaug
On 07/04/2017 04:47 PM, Dexter wrote: Hi everyone! Could you tell me please, how I can clearly convert char (&name)[N] to nsACString? I tried this: char* cname = new char[N]; memcpy(cname, &name, N); nsAutoString strName; strName.AssignWithConversion(cname, N); I can't find out how to get ns

Re: Converting const char (&name)[N] to nsACString

2017-07-04 Thread Honza Bambas
Use NS_NAMED_LITERAL_CSTRING, see [1] for plenty of examples. -hb- [1] https://dxr.mozilla.org/mozilla-central/search?q=NS_NAMED_LITERAL_CSTRING&case=false On 7/4/17 3:47 PM, Dexter wrote: Hi everyone! Could you tell me please, how I can clearly convert char (&name)[N] to nsACString? I t

Converting const char (&name)[N] to nsACString

2017-07-04 Thread Dexter
Hi everyone! Could you tell me please, how I can clearly convert char (&name)[N] to nsACString? I tried this: char* cname = new char[N]; memcpy(cname, &name, N); nsAutoString strName; strName.AssignWithConversion(cname, N); I can't find out how to get nsACString. I could use nsACString instead