On Fri, Apr 18, 2008 at 08:39:10PM -0600, ChadDavis wrote:
> >
> > I just wonder if this is supposed to be used where 'svn export' better
> > be.
> >
> >
>
> No, its the Sysdeo tomcat plugin's export WAR file feature. it doesn't, as
> far as I can tell, have a mechanism for filtering out things l
>
> I just wonder if this is supposed to be used where 'svn export' better
> be.
>
>
No, its the Sysdeo tomcat plugin's export WAR file feature. it doesn't, as
far as I can tell, have a mechanism for filtering out things like .svn.
On Fri, Apr 18, 2008 at 10:27:30AM -0600, ChadDavis wrote:
> I have a simple bash scripting question.
>
> I have a tree of directories from which I would like to recursively dig
> into, removing source control meta-information from. In this case, the
> meta-data is in .svn folders.
I just wonder
Jochen Schulz wrote:
Ken Irving:
If you want to remove the .svn/ directories and everything within them,
something
like this should work (remove the 'echo' if the output looks ok):
$ cd starting/directory
$ find . -type d -name .svn -exec echo rm -r {} \;
GNU find also accepts the parame
Ken Irving:
>
> If you want to remove the .svn/ directories and everything within them,
> something
> like this should work (remove the 'echo' if the output looks ok):
>
> $ cd starting/directory
> $ find . -type d -name .svn -exec echo rm -r {} \;
GNU find also accepts the parameter (or be
Good to know. Thank.
On Fri, Apr 18, 2008 at 11:49 AM, Bob McGowan <[EMAIL PROTECTED]>
wrote:
> ChadDavis wrote:
>
> > I have a simple bash scripting question.
> >
> > I have a tree of directories from which I would like to recursively dig
> > into, removing source control meta-information from.
ChadDavis wrote:
I have a simple bash scripting question.
I have a tree of directories from which I would like to recursively dig
into, removing source control meta-information from. In this case, the
meta-data is in .svn folders.
Does anyone have any elegant suggestions on how to do this?
On Fri, Apr 18, 2008 at 10:27:30AM -0600, ChadDavis wrote:
> I have a simple bash scripting question.
>
> I have a tree of directories from which I would like to recursively dig into,
> removing source
> control meta-information from. In this case, the meta-data is in .svn
> folders.
>
> Does
That's great. I also saw in Unix Power Tools that you can use xargs to
similar effect?
On Fri, Apr 18, 2008 at 10:55 AM, Martin Kraus <[EMAIL PROTECTED]> wrote:
> On Fri, Apr 18, 2008 at 10:27:30AM -0600, ChadDavis wrote:
> > I have a simple bash scripting question.
> >
> > I have a tree of dire
Am 2006-12-07 15:20:26, schrieb H.S.:
> Stephen R Laniel wrote:
> >find directoryName -mtime +X -print0 |xargs -0 rm '{}'
This can handel daily files for unlimited years
> $> find directoryName -mtime +X -exec rm -f '{}' \;
This can handel only files from the last 15 years :-P
Thanks, Greeti
The '-print0' of 'find' and the '-0' of 'xargs' (those are the number
zero, not a capital o) prevent problems processing file names that
contain white space (such as you might get from other OS's, but can also
get on UNIX/Linux systems when using GUI programs that create files).
It uses a 'nul
* Almut Behrens <[EMAIL PROTECTED]> [2006 Dec 07 16:08 -0600]:
> On Thu, Dec 07, 2006 at 03:41:53PM -0600, Ron Johnson wrote:
> >
> > OP specifically noted:
> > I'm not interested in the actual created/modified date
The reason for that was so I don't clobber other files that may be
older, jus
On Thu, Dec 07, 2006 at 03:41:53PM -0600, Ron Johnson wrote:
> -BEGIN PGP SIGNED MESSAGE-
> Hash: SHA1
>
> On 12/07/06 15:12, Almut Behrens wrote:
> > On Thu, Dec 07, 2006 at 12:16:54PM -0600, Nate Bargmann wrote:
> >> I have a directory of files that are created daily using
> >> filename
-BEGIN PGP SIGNED MESSAGE-
Hash: SHA1
On 12/07/06 15:12, Almut Behrens wrote:
> On Thu, Dec 07, 2006 at 12:16:54PM -0600, Nate Bargmann wrote:
>> I have a directory of files that are created daily using
>> filename-`date +%Y%m%d`.tar.gz so I have a directory with files whose
>> names adva
On Thu, Dec 07, 2006 at 11:41:23AM -0700, John Schmidt wrote:
> On Thursday 07 December 2006 11:16, Nate Bargmann wrote:
> > Since there is a lot of knowledge on this list, I thought I'd aske
> > here.
> >
> > This may be trivial, but I'm not even sure how to search for what I
> > want to do.
> >
>
On Thu, Dec 07, 2006 at 12:16:54PM -0600, Nate Bargmann wrote:
>
> I have a directory of files that are created daily using
> filename-`date +%Y%m%d`.tar.gz so I have a directory with files whose
> names advance from filename-20061201.tar.gz to filename-20061202.tar.gz
> to filename-20061203.tar.
On Thu, Dec 07, 2006 at 07:57:29PM +0100, Albert Dengg wrote:
> On Thu, Dec 07, 2006 at 12:16:54PM -0600, Nate Bargmann wrote:
> > Since there is a lot of knowledge on this list, I thought I'd aske
> > here.
> >
> > This may be trivial, but I'm not even sure how to search for what I
> > want to do
Stephen R Laniel wrote:
The easiest way wouldn't involve the filename at all. If you
know that a file created on date D is stamped with date D --
i.e., if your files all look like so:
(13:09) [EMAIL PROTECTED]:~$ ls filename-20061207.tar.gz
-rw-r--r-- 1 slaniel slaniel 0 2006-12-07 13:09 file
On Thu, Dec 07, 2006 at 12:16:54PM -0600, Nate Bargmann wrote:
> Since there is a lot of knowledge on this list, I thought I'd aske
> here.
>
> This may be trivial, but I'm not even sure how to search for what I
> want to do.
>
> I have a directory of files that are created daily using
> filenam
Nate Bargmann wrote:
I have a directory of files that are created daily using
filename-`date +%Y%m%d`.tar.gz so I have a directory with files whose
names advance from filename-20061201.tar.gz to filename-20061202.tar.gz
to filename-20061203.tar.gz and so on. Based on the date in the
filename, I
-BEGIN PGP SIGNED MESSAGE-
Hash: SHA1
On 12/07/06 12:16, Nate Bargmann wrote:
> Since there is a lot of knowledge on this list, I thought I'd aske
> here.
>
> This may be trivial, but I'm not even sure how to search for what I
> want to do.
>
> I have a directory of files that are create
On Thursday 07 December 2006 11:16, Nate Bargmann wrote:
> Since there is a lot of knowledge on this list, I thought I'd aske
> here.
>
> This may be trivial, but I'm not even sure how to search for what I
> want to do.
>
> I have a directory of files that are created daily using
> filename-`date +
On Thu, Dec 07, 2006 at 12:16:54PM -0600, Nate Bargmann wrote:
> I have a directory of files that are created daily using
> filename-`date +%Y%m%d`.tar.gz so I have a directory with files whose
> names advance from filename-20061201.tar.gz to filename-20061202.tar.gz
> to filename-20061203.tar.gz
kmself@ix.netcom.com wrote:
>The key difference is that $( command list ) is nestable without
>quoting, backticks are not.
[snip]
>The functionality is common in a number of shells other than bash,
>though I'm not quite sure which. I believe the Unix posix-compliant
>(bastardized korn) and possi
On Fri, Jun 23, 2000 at 08:51:44PM -0400, Peter Kovacs wrote:
> On Sat, 24 Jun 2000, Mark Phillips wrote:
> > for f in $(cd
>
> From man 1 bash:
>Command Substitution
>Command substitution allows the output of a command to
>replace the command name. There are two
Andre Berger <[EMAIL PROTECTED]> writes:
Sorry, use
kill -9 $(pidof communicator-smotif.real)
or something like that.
Andre
> Peter Kovacs <[EMAIL PROTECTED]> writes:
>
> > On Sat, 24 Jun 2000, Mark Phillips wrote:
> > From man 1 bash:
> >Command Substitution
> >Command
** On Jun 24, Mark Phillips scribbled:
> Peter Kovacs [EMAIL PROTECTED] wrote:
> > On Fri, 23 Jun 2000, Peter Kovacs wrote:
> >
> > > I'm sure that a fix has already been posted, but this works for me
> > > (replace the code above with this):
> > >
> > > for d in /usr/lib/netscape/base-4/
** On Jun 24, Mark Phillips scribbled:
> Corey Popelier [EMAIL PROTECTED] wrote:
>
> > Yes I have this problem also. I assume we shall await a fix. And use
> > Mozilla in the meantime :)
[snip]
> And the problem seems to be with a syntax error at the line
>
> for f in (cd $d;ls -1
Peter Kovacs <[EMAIL PROTECTED]> writes:
> On Sat, 24 Jun 2000, Mark Phillips wrote:
> From man 1 bash:
>Command Substitution
>Command substitution allows the output of a command to
>replace the command name. There are two forms:
>
> $(command)
>or
>
On Fri, Jun 23, 2000 at 08:51:44PM -0400, Peter Kovacs wrote
> On Sat, 24 Jun 2000, Mark Phillips wrote:
>
> > What does "YMMV" stand for?
>
> YMMV = Your Mileage May Vary
>
> > An official fix has come through, and what it does is replace
> >
> > for f in (cd.
> >
> > by
> >
> >
On Sat, 24 Jun 2000, Mark Phillips wrote:
> What does "YMMV" stand for?
YMMV = Your Mileage May Vary
> An official fix has come through, and what it does is replace
>
> for f in (cd.
>
> by
>
> for f in $(cd
From man 1 bash:
Command Substitution
Command substitu
Peter Kovacs [EMAIL PROTECTED] wrote:
> On Fri, 23 Jun 2000, Peter Kovacs wrote:
>
> > I'm sure that a fix has already been posted, but this works for me
> > (replace the code above with this):
> >
> > for d in /usr/lib/netscape/base-4/wrapper.d ; do
> > cd $d;
> >
On Sat, 24 Jun 2000, Mark Phillips wrote:
> for d in \
> /usr/lib/netscape/base-4/wrapper.d \
> /usr/lib/netscape/$VER \
> /usr/lib/netscape/$VER/$BIN ;do
> for f in (cd $d;ls -1 . | sort); do
> . $d/$f
> done
> done
I'm sure
33 matches
Mail list logo
