I forgot, I was not trying to use this. Its seems to me very unsual. I was
just checking that what was stated on the book and learned anew thing.
regards
J.A.Serralheiro
actually im reading "Software engineering in c" by peter darnell. its
pretty basic. It was
because I was reading this that this problem arised.
Thanks every one for the detailed explanation.
You need to allocate memory for the destination. strcpy just copies
bytes from one location to another -- *both* must be valid memory
locations and may not overlap (undefined behavior).
Go to comp.lang.c *and* read the FAQ.
--
Eric G. Miller
"J.A.Serralheiro" <[EMAIL PROTECTED]> writes:
> /*Hi folks. Heres a very odd trouble ( for me at least)
> I was reading a book where it was stated that
> " char *ptr = "text"; " is an allowed declaration and that
> the compiler automatically allocates space for the string text and for th
* J.A.Serralheiro ([EMAIL PROTECTED]) spake thusly:
[ char * non-writable ]
RTFFAQ, or e.g. Thinking in C++. Or do 'man gcc' and search for
-fwritable-strings flag.
Explanation: by default gcc places character array literals into
read-only memory. Attempt to write to that memory causes segfault.
On Tue, Aug 07, 2001 at 03:20:52PM +0100, J.A.Serralheiro wrote:
> /*Hi folks. Heres a very odd trouble ( for me at least)
> I was reading a book where it was stated that
> " char *ptr = "text"; " is an allowed declaration and that
> the compiler automatically allocates space for the str
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