Well, Mitch did a darn good job of explaining all of this, but I'll still
throw in my two cents...
>Question 1. Is the calculation: = speed> div correct ? (ie. 512K / 33.6K = 15.238...
>users)
Like Mitch said, this assumes that everyone's going to be downloading at the
same time. Since you sa
Thanks for the complete and very speedy response Mitch - now I know why I
use and preach Debian !!!
Ivan.
ivan wrote:
> Hello All,
>
> Myself and a group of friends wish to connect to WWW by using a permanent
> connection but if we all have 33.6K modems and are all connected then it
> seems that we require at least a 512K connection which is prohibitively
> expensive !
>
> Question 1. Is the calcula
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