Tzafrir Cohen wrote:
> On Sun, Dec 21, 2008 at 04:45:21PM -0600, Ron Johnson wrote:
>> On 12/21/08 15:58, Jörg-Volker Peetz wrote:
>>> $ seq -w 1 1 10 | xargs -i -n1 cp file.jpg file{}.jpg
>> What's with the {}? An implied variable?
>
> $ LANG=C man xargs | grep -C 2 '{}'
>-i[replace-str]
2008/12/14, Rodolfo Medina :
> I need the right syntax to copy file.jpg 100 times with one command so to
> get
> 100 files named file1.jpg, file2.jpg, ..., file100.jpg.
>
> Can anybody suggest how to achieve that?
You could try something like:
cat file.pdf | tee `seq -w 0 100 | sed 's+.*+file_&.p
On Sun, Dec 21, 2008 at 04:45:21PM -0600, Ron Johnson wrote:
> On 12/21/08 15:58, Jörg-Volker Peetz wrote:
>> $ seq -w 1 1 10 | xargs -i -n1 cp file.jpg file{}.jpg
>
> What's with the {}? An implied variable?
$ LANG=C man xargs | grep -C 2 '{}'
-i[replace-str]
This option i
On 12/21/08 15:58, Jörg-Volker Peetz wrote:
Osamu Aoki wrote:
On Sat, Dec 13, 2008 at 09:13:07PM +, Tzafrir Cohen wrote:
On Sun, Dec 14, 2008 at 03:50:31AM +0900, Osamu Aoki wrote:
On Sat, Dec 13, 2008 at 07:12:32PM +, Rodolfo Medina wrote:
I need the right syntax to copy file.jpg 100
Osamu Aoki wrote:
> On Sat, Dec 13, 2008 at 09:13:07PM +, Tzafrir Cohen wrote:
>> On Sun, Dec 14, 2008 at 03:50:31AM +0900, Osamu Aoki wrote:
>>> On Sat, Dec 13, 2008 at 07:12:32PM +, Rodolfo Medina wrote:
I need the right syntax to copy file.jpg 100 times with one command so to
Thomas Preud'homme wrote:
> filevar=$1 # The file to copy a hundred time
> basefile=${filevar%.[^.]*} # We delete all the end from the last dot (eg
> a dot followed by any others caracters)
> extension=${filevar##^.*.} # We delete all the beginning until the last
Just for refere
Thomas Preud'homme wrote:
> The Saturday 13 December 2008 20:12:32 Rodolfo Medina, you wrote :
>> I need the right syntax to copy file.jpg 100 times with one command so to
>> get 100 files named file1.jpg, file2.jpg, ..., file100.jpg.
>>
>> Can anybody suggest how to achieve that?
>>
>> Thanks for
Rick Pasotto wrote:
>
> I forgot about seq. This is even better (the -w left pads with zero for
> equal width):
>
> for x in $(seq -w 1 100); do cp file.jpg file${x}.jpg; done
>
correction^
Nice! Something I have been looking for quite some time. I was u
On Sat, Dec 13, 2008 at 09:13:07PM +, Tzafrir Cohen wrote:
> On Sun, Dec 14, 2008 at 03:50:31AM +0900, Osamu Aoki wrote:
> > On Sat, Dec 13, 2008 at 07:12:32PM +, Rodolfo Medina wrote:
> > > I need the right syntax to copy file.jpg 100 times with one command so to
> > > get
> > > 100 files
Hi Rick,
On Sat, Dec 13, 2008 at 7:41 PM, Rick Pasotto wrote:
> I forgot about seq. This is even better (the -w left pads with zero for
> equal width):
>
> for x in $(seq -w 1 100); do cp file.jpg file${c}.jpg; done
Waw! Great one-liner.
BTW: Guess you meant file${x}.jpg;
Greetings, Manon.
On Sat, Dec 13, 2008 at 09:13:07PM +, Tzafrir Cohen wrote:
> On Sun, Dec 14, 2008 at 03:50:31AM +0900, Osamu Aoki wrote:
> > On Sat, Dec 13, 2008 at 07:12:32PM +, Rodolfo Medina wrote:
> > > I need the right syntax to copy file.jpg 100 times with one command so to
> > > get
> > > 100 files
On Sun, Dec 14, 2008 at 03:50:31AM +0900, Osamu Aoki wrote:
> On Sat, Dec 13, 2008 at 07:12:32PM +, Rodolfo Medina wrote:
> > I need the right syntax to copy file.jpg 100 times with one command so to
> > get
> > 100 files named file1.jpg, file2.jpg, ..., file100.jpg.
> >
> > Can anybody sugge
The Saturday 13 December 2008 20:12:32 Rodolfo Medina, you wrote :
> I need the right syntax to copy file.jpg 100 times with one command so to
> get 100 files named file1.jpg, file2.jpg, ..., file100.jpg.
>
> Can anybody suggest how to achieve that?
>
> Thanks for any reply
> Rodolfo
filevar="fil
On Sat, Dec 13, 2008 at 07:12:32PM +, Rodolfo Medina wrote:
> I need the right syntax to copy file.jpg 100 times with one command so to get
> 100 files named file1.jpg, file2.jpg, ..., file100.jpg.
>
> Can anybody suggest how to achieve that?
ere is one without looping :-)
$ seq 1 100 | sed
Rodolfo writes:
> I need the right syntax to copy file.jpg 100 times with one command so to
> get 100 files named file1.jpg, file2.jpg, ..., file100.jpg.
for I in {1..100}; do cp file.jpg file$I.jpg ; done
But what are you actually trying to achieve?
--
John Hasler
--
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On Sat, Dec 13, 2008 at 07:35:44PM +0100, Manon Metten wrote:
> Hi Rodolfo
>
> On Sat, Dec 13, 2008 at 8:12 PM, Rodolfo Medina
> wrote:
>
> > I need the right syntax to copy file.jpg 100 times with one command so to
> > get
> > 100 files named file1.jpg, file2.jpg, ..., file100.jpg.
>
>
> #!/
Hi Rodolfo
On Sat, Dec 13, 2008 at 8:12 PM, Rodolfo Medina
wrote:
> I need the right syntax to copy file.jpg 100 times with one command so to get
> 100 files named file1.jpg, file2.jpg, ..., file100.jpg.
#!/bin/bash
for x in `seq 1 100`; do
if [[ x -lt 10 ]]; then cp file.jpg file-00$x.
On Sat, Dec 13, 2008 at 07:12:32PM +, Rodolfo Medina wrote:
> I need the right syntax to copy file.jpg 100 times with one command so to get
> 100 files named file1.jpg, file2.jpg, ..., file100.jpg.
>
> Can anybody suggest how to achieve that?
c=0; while [ $c -lt 100 ]; do c=$[c + 1]; n='000'$
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