On Sat, Apr 17, 2010 at 12:02:40PM -0400, Daniel D Jones wrote:
> On Saturday 17 April 2010 00:09:28 Michael Elkins wrote:
> > On Fri, Apr 16, 2010 at 08:15:38PM -0400, Daniel D Jones wrote:
> > >What I'm trying to do is pretty simple. Getting it to work is turning out
> > > not to be. What I wan
* 2010-04-17 09:34 (-0700), Michael Elkins wrote:
> You can run into that sort of problem if your pattern to replace
> contains any forward slashes (/) in it. If you need to such an
> expansion, you probably want to do it in two passes, first doing a / to
> \/ substitution on your replacement str
Daniel D Jones wrote:
> What I want to do is call a bash script with a couple of arguments, and,
> within the script, call sed to use those args to replace two
> placeholders in a file:
> bashscript SUB1 SUB2
> This line inside bashscript doesn't work:
> sed -e 's/PLACEHOLDER1/$1/' -e 's/PLACEHO
On Sat, Apr 17, 2010 at 12:02:40PM -0400, Daniel D Jones wrote:
That was the first thing I tried and sed gave me an error:
sed: -e expression #1, char 18: unknown option to `s'
I just went back and tried it again and it worked, so I have no idea what I
did the first time that made it not work.
On Saturday 17 April 2010 00:09:28 Michael Elkins wrote:
> On Fri, Apr 16, 2010 at 08:15:38PM -0400, Daniel D Jones wrote:
> >What I'm trying to do is pretty simple. Getting it to work is turning out
> > not to be. What I want to do is call a bash script with a couple of
> > arguments, and, withi
On Fri, Apr 16, 2010 at 08:15:38PM -0400, Daniel D Jones wrote:
What I'm trying to do is pretty simple. Getting it to work is turning out not
to be. What I want to do is call a bash script with a couple of arguments,
and, within the script, call sed to use those args to replace two placeholders
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