Am 2006-05-09 09:26:38, schrieb [EMAIL PROTECTED]:
> Now if only I could get aptitude to understand that I really only need
> one copy of /usr/share ...
I think, this will not work...
And yes, /usr/share can be shared between MACHINES,
BUT there WILL be problems between RELEASES...
Greetings
On Sun, May 07, 2006 at 03:26:52PM +0200, Michelle Konzack wrote:
> Am 2006-05-04 08:25:48, schrieb [EMAIL PROTECTED]:
>
> > Thanks. That worked. Why do I need it? Because I have just one home
> > directory, NFS-mounted and shared between two machines with different
> > architectures. I find
Am 2006-05-04 08:25:48, schrieb [EMAIL PROTECTED]:
> Thanks. That worked. Why do I need it? Because I have just one home
> directory, NFS-mounted and shared between two machines with different
> architectures. I find it convenient for everything except compiling.
I do this too... exactly,
On Tue, Apr 25, 2006 at 06:56:27PM +0200, Dennis Stosberg wrote:
> [EMAIL PROTECTED] wrote:
>
> > I'd like to define a symbol ARCH in my Makefile to be the output
> > of
> > uname -m
> >
> > The obvious thing, just starting with
> >
> > ARCH = `uname -m`
> >
> > didn't seem to work. It defi
On Tue, Apr 25, 2006 at 06:56:27PM +0200, Dennis Stosberg wrote:
> [EMAIL PROTECTED] wrote:
>
> > I'd like to define a symbol ARCH in my Makefile to be the output
> > of
> > uname -m
> >
> > The obvious thing, just starting with
> >
> > ARCH = `uname -m`
> >
> > didn't seem to work. It defi
[EMAIL PROTECTED] wrote:
> I'd like to define a symbol ARCH in my Makefile to be the output of
> uname -m
>
> The obvious thing, just starting with
>
> ARCH = `uname -m`
>
> didn't seem to work. It defined ARCH to be `uname -m' instead of
> i686 or x86_64. Not unreasonable, but What *is
[EMAIL PROTECTED] wrote:
> I'd like to define a symbol ARCH in my Makefile to be the output
> of
> uname -m
>
> The obvious thing, just starting with
>
> ARCH = `uname -m`
>
> didn't seem to work. It defined ARCH to be `uname -m' instead of
> i686 or x86_64. Not unreasonable, but What *is*
On Tue, Apr 25, 2006 at 11:25:23AM -0400, [EMAIL PROTECTED] wrote:
> I'd like to define a symbol ARCH in my Makefile to be the output of
> uname -m
>
> The obvious thing, just starting with
>
> ARCH = `uname -m`
>
> didn't seem to work. It defined ARCH to be `uname -m' instead of
> i686 o
I'd like to define a symbol ARCH in my Makefile to be the output of
uname -m
The obvious thing, just starting with
ARCH = `uname -m`
didn't seem to work. It defined ARCH to be `uname -m' instead of
i686 or x86_64. Not unreasonable, but What *is* the way to do this?
-- hendrik
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