On Sat, Apr 17, 2010 at 12:02:40PM -0400, Daniel D Jones wrote:
> On Saturday 17 April 2010 00:09:28 Michael Elkins wrote:
> > On Fri, Apr 16, 2010 at 08:15:38PM -0400, Daniel D Jones wrote:
> > >What I'm trying to do is pretty simple. Getting it to work is turning out
> > > not to be. What I wan
* 2010-04-17 09:34 (-0700), Michael Elkins wrote:
> You can run into that sort of problem if your pattern to replace
> contains any forward slashes (/) in it. If you need to such an
> expansion, you probably want to do it in two passes, first doing a / to
> \/ substitution on your replacement str
Daniel D Jones wrote:
> What I want to do is call a bash script with a couple of arguments, and,
> within the script, call sed to use those args to replace two
> placeholders in a file:
> bashscript SUB1 SUB2
> This line inside bashscript doesn't work:
> sed -e 's/PLACEHOLDER1/$1/' -e 's/PLACEHO
On Sat, Apr 17, 2010 at 12:02:40PM -0400, Daniel D Jones wrote:
That was the first thing I tried and sed gave me an error:
sed: -e expression #1, char 18: unknown option to `s'
I just went back and tried it again and it worked, so I have no idea what I
did the first time that made it not work.
On Saturday 17 April 2010 00:09:28 Michael Elkins wrote:
> On Fri, Apr 16, 2010 at 08:15:38PM -0400, Daniel D Jones wrote:
> >What I'm trying to do is pretty simple. Getting it to work is turning out
> > not to be. What I want to do is call a bash script with a couple of
> > arguments, and, withi
On Fri, Apr 16, 2010 at 08:15:38PM -0400, Daniel D Jones wrote:
What I'm trying to do is pretty simple. Getting it to work is turning out not
to be. What I want to do is call a bash script with a couple of arguments,
and, within the script, call sed to use those args to replace two placeholders
What I'm trying to do is pretty simple. Getting it to work is turning out not
to be. What I want to do is call a bash script with a couple of arguments,
and, within the script, call sed to use those args to replace two placeholders
in a file:
bashscript SUB1 SUB2
This line inside bashscript
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