Re: D por Android

2012-03-06 Thread Iain Buclaw
On 6 March 2012 14:43, Dejan Lekic wrote: > Lol Ian, you made me laugh mate! :) I please, therefore I am. ;-) -- Iain Buclaw *(p < e ? p++ : p) = (c & 0x0f) + '0';

Re: D por Android

2012-03-06 Thread Dejan Lekic
Lol Ian, you made me laugh mate! :)