On Thu, Jan 11, 2007 at 11:38:18AM -0800, jim wrote:
>I have recently upgraded from 1.5.12 to 1.5.23 and noticed something that
>has me wondering.I compiled this on 1.5.23 and have run it under cmd.exe
>on on 1.5.12 and 1.5.23:
>
>#include
>
>int main(int argc, char *argv[])
>{
> int i, c;
>
placed grep with the program
> to print out argv and noticed the difference.
>
> thanks,
> jim
>
>> -Original Message-
>> From: Morgan Gangwere [mailto:[EMAIL PROTECTED]
>> Sent: Thursday, January 11, 2007 4:32 PM
>> To: cygwin@cygwin.com
>>
n com
^^^
<http://cygwin.com/acronyms/#PCYMTNQREAIYR>. No one wants the spam. Thanks.
Subject: Re: command line arg expansion
jim wrote:
I have recently upgraded from 1.5.12 to 1.5.23 and noticed
something that
has me wondering.I compiled this on 1.5.23 and have run
it under
ly - maybe it's something else?
thanks for any insight,
jim
> -Original Message-
> From: Larry Hall (Cygwin) [mailto:[EMAIL PROTECTED]
> Sent: Thursday, January 11, 2007 12:37 PM
> To: cygwin@cygwin.com
> Subject: Re: command line arg expansion
>
> jim wrote
-BEGIN PGP SIGNED MESSAGE-
Hash: SHA1
jim wrote:
> I have recently upgraded from 1.5.12 to 1.5.23 and noticed something that
> has me wondering.I compiled this on 1.5.23 and have run it under cmd.exe
> on on 1.5.12 and 1.5.23:
>
> #include
>
> int main(int argc, char *argv[])
> {
>
jim wrote:
I have recently upgraded from 1.5.12 to 1.5.23 and noticed something that
has me wondering.I compiled this on 1.5.23 and have run it under cmd.exe
on on 1.5.12 and 1.5.23:
#include
int main(int argc, char *argv[])
{
int i, c;
for (i = 0; i < argc; i++)
printf("arg[%
I have recently upgraded from 1.5.12 to 1.5.23 and noticed something that
has me wondering.I compiled this on 1.5.23 and have run it under cmd.exe
on on 1.5.12 and 1.5.23:
#include
int main(int argc, char *argv[])
{
int i, c;
for (i = 0; i < argc; i++)
printf("arg[%d]: '%s'\n",
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