Re: grep -P regexp problem

Andriy Sen hotmail.com> writes: > G:\>cat test.s | grep -P "^(|[^0])1" > 1 Useless use of cat. It is more efficient to write: grep -P "^(|[^0])1" test.s -- Eric Blake -- Unsubscribe info: http://cygwin.com/ml/#unsubscribe-simple Problem reports: http://cygwin.com/problems.html

Re: grep -P regexp problem

This is not cygwin-specific, so it is really OT for this list, that being said... Sorry. I will try to figure out where to go then. grep -P treats the whole input as a single string, and outputs the line (or lines) containing the match for the pattern. [^0] matches ANYTHING except 0, inc

Re: grep -P regexp problem

Den 2009-03-03 19:26 skrev Andriy Sen: Below is an example of the problem. G:\>grep -V GNU grep 2.5.3 Copyright (C) 1988, 1992-2002, 2004, 2005 Free Software Foundation, Inc. This is free software; see the source for copying conditions. There is NO warranty; not even for MERCHANTABILITY or F

RE: grep -P regexp problem

Andriy Sen wrote: > Below is an example of the problem. > > G:\>cat test.s > a > 1 > > G:\>cat test.s | grep -P "[^0]1" > a > 1 This is not cygwin-specific, so it is really OT for this list, that being said... grep -P treats the whole input as a single string, and outputs the line (or lines) con