Configuration Information [Automatically generated, do not change]:
Machine: x86_64
OS: linux-gnu
Compiler: gcc-11
Compilation CFLAGS: -DSSH_SOURCE_BASHRC
uname output: Linux lex 6.5.0-25-generic #25-Ubuntu SMP PREEMPT_DYNAMIC Wed Feb
7 14:58:39 UTC 2024 x86_64 x86_64 x86_64 GNU/Linux
Machine Typ
[Apologies, an earlier edition of this bug report was sent from the address
a...@lex.03s.net, which can only be replied to from my internal network.
Please ignore that report. Thanks much!]
Configuration Information [Automatically generated, do not change]:
Machine: x86_64
OS: linux-gnu
Compiler:
On Sun, 10 Mar 2024 23:09:37 +0800
Adrian Ho wrote:
> [Apologies, an earlier edition of this bug report was sent from the address
> a...@lex.03s.net, which can only be replied to from my internal network.
> Please ignore that report. Thanks much!]
>
> Configuration Information [Automatically gen
On Sun, Mar 10, 2024 at 1:51 PM Kerin Millar wrote:
> $ y() { local -g a; a=123; echo "inner: $a"; }
> $ x; echo "outermost: $a"
> inner: 123
> outer: 123
> outermost:
>
> This may not be. There, the effect of the -g option effectively ends at the
> outermost scope in which the variable, a, was d
On Sun, Mar 10, 2024, at 1:51 PM, Kerin Millar wrote:
> Dynamic scoping can be tremendously confusing. The following examples
> should help to clarify the present state of affairs.
>
> $ x() { local a; y; echo "outer: $a"; }
> $ y() { local a; a=123; echo "inner: $a"; }
> $ x; echo "outermost: $a"
On Sun, Mar 10, 2024 at 04:01:10PM -0400, Lawrence Velázquez wrote:
> Basically, without an assignment, "local -g" does nothing.
Well, the original purpose of -g was to create variables, especially
associative arrays, at the global scope from inside a function.
I think this thread has been asking
On Sun, Mar 10, 2024, at 5:36 PM, Greg Wooledge wrote:
> Here it is in action. "local -g" (or "declare -g") without an assignment
> in the same command definitely does things.
>
> hobbit:~$ f() { declare -g var; var=in_f; }
> hobbit:~$ unset -v var; f; declare -p var
> declare -- var="in_f"
This
On Sun, Mar 10, 2024 at 06:39:19PM -0400, Lawrence Velázquez wrote:
> On Sun, Mar 10, 2024, at 5:36 PM, Greg Wooledge wrote:
> > Here it is in action. "local -g" (or "declare -g") without an assignment
> > in the same command definitely does things.
> >
> > hobbit:~$ f() { declare -g var; var=in_f
Configuration Information [Automatically generated, do not change]:
Machine: x86_64
OS: msys
Compiler: gcc
Compilation CFLAGS: -march=nocona -msahf -mtune=generic -O2 -pipe
-D_STATIC_BUILD
uname output: MINGW64_NT-10.0-19045 Zack2021HPPavilion 3.4.10.x86_64
2024-02-10 08:39 UTC x86_64 Msys
Machine
On Sun, 10 Mar 2024 16:01:10 -0400
Lawrence Velázquez wrote:
> On Sun, Mar 10, 2024, at 1:51 PM, Kerin Millar wrote:
> > Dynamic scoping can be tremendously confusing. The following examples
> > should help to clarify the present state of affairs.
> >
> > $ x() { local a; y; echo "outer: $a"; }
On Sun, 10 Mar 2024 17:36:13 -0400
Greg Wooledge wrote:
> On Sun, Mar 10, 2024 at 04:01:10PM -0400, Lawrence Velázquez wrote:
> > Basically, without an assignment, "local -g" does nothing.
>
> Well, the original purpose of -g was to create variables, especially
> associative arrays, at the globa
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