Without sounding alarmist, I can break my machine using bash. I also have a
fix. I shall be officially releasing the c code this weekend at the
hackathon london.
As my code following correctly implements the logic the dos attack vector
is negated.
The replacement code
/*Do openql maths Now*/
On Tue, Mar 20, 2012 at 04:47:51PM +, Eamonn Smyth wrote:
> Without sounding alarmist, I can break my machine using bash. I also have a
> fix. I shall be officially releasing the c code this weekend at the
> hackathon london.
You included some C++ code (or possibly C code, if you're allowed to
Am 20.03.2012 17:47, schrieb Eamonn Smyth:
Without sounding alarmist, I can break my machine using bash. I also have a
fix. I shall be officially releasing the c code this weekend at the
hackathon london.
As my code following correctly implements the logic the dos attack vector
is negated.
The
Am 20.03.2012 18:04, schrieb Greg Wooledge:
On Tue, Mar 20, 2012 at 04:47:51PM +, Eamonn Smyth wrote:
Without sounding alarmist, I can break my machine using bash. I also have a
fix. I shall be officially releasing the c code this weekend at the
hackathon london.
You included some C++ code
On Tue, Mar 20, 2012 at 06:47:17PM +0100, dethrophes wrote:
> Secondly when you say dos? you mean a windows command prompt or you
> actually mean DOS 6.22, dosbox, or a text box what do you consider dos?.
He meant DoS, or "Denial of Service". He believes he has found some sort
of security bug/ex
Thanks Greg that makes more sense.
I would have recognised DoS, dos though :) showing my age I guess.
I'm inclined to doubt though that it can be defined as a Bash DoS
whatever it is, otherwise a lot of installation/bash scripts would be up
for the chop ;).
Am 20.03.2012 19:00, schrieb Greg W
2012-03-20 16:47:51 +, Eamonn Smyth:
> Without sounding alarmist, I can break my machine using bash. I also have a
> fix. I shall be officially releasing the c code this weekend at the
> hackathon london.
[...]
A DOS vector often found is bash *scripts* is when a script
takes user input in a v
On 3/20/12 2:17 PM, Stephane Chazelas wrote:
> 2012-03-20 16:47:51 +, Eamonn Smyth:
>> Without sounding alarmist, I can break my machine using bash. I also have a
>> fix. I shall be officially releasing the c code this weekend at the
>> hackathon london.
> [...]
>
> A DOS vector often found is
On 3/19/12 9:27 AM, Mark Edgar wrote:
> I've boiled the problem down to this:
>
> A=
> B=q
> echo "x${A+${B#q*}}x" | sed -nel
>
> Excluding the newline, the output I expect is "xx", but instead there
> is a delete character \177 between the two "x" characters.
Thanks for the wonderfully detai
Configuration Information [Automatically generated, do not change]:
Machine: i686
OS: linux-gnu
Compiler: gcc
Compilation CFLAGS: -DPROGRAM='bash' -DCONF_HOSTTYPE='i686'
-DCONF_OSTYPE='linux-gnu' -DCONF_MACHTYPE='i686-pc-linux-gnu' -DC$
uname output: Linux lalgec 3.0.0-16-generic-pae #29-Ubuntu S
I have bash-4.2.tar.gz What inside this, All source code .c/.h ,
configuration file. I want to find where is the print standard output
function and add my script like sed 's,Hello,Hi,gI'before it printed. The
result will be every standard output with the hello word will change to Hi
word.
--
View
not sure if its what your looking for but you could look at
builtins/printf.def
as a starting point. it implements the printf builtin function.
Am 20.03.2012 20:29, schrieb runicer:
I have bash-4.2.tar.gz What inside this, All source code .c/.h ,
configuration file. I want to find where is the
On 3/20/12 12:37 PM, Jurij Mihelič wrote:
> Configuration Information [Automatically generated, do not change]:
> Machine: i686
> OS: linux-gnu
> Compiler: gcc
> Compilation CFLAGS: -DPROGRAM='bash' -DCONF_HOSTTYPE='i686'
> -DCONF_OSTYPE='linux-gnu' -DCONF_MACHTYPE='i686-pc-linux-gnu' -DC$
> unam
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